Okay, me being me, I've forgotten the major amount of physics I learnt, in particular, specific heat capacity.

 

so, it would be agreat help if someone could give me some means of working this out.

 

Calculate the thermal energy required to convert 5 kg of ice at 0 degrees celsius to steam at 100 degrees celsius. (specific heat capacity © of ice = C of steam = 2100 J\Kg\K, specific heat capacity © of water = 4200 J\Kg\K, Latent heat of vapourisation = 2.3 X 10^6 J\Kg, Latent heat of fusion = 3.3 X 10^5 J\Kg

 

 

thanks...

the answer yes, the number is 3

Miseria_ said in post #1 :

Okay, me being me, I've forgotten the major amount of physics I learnt, in particular, specific heat capacity.

 

so, it would be agreat help if someone could give me some means of working this out.

 

Calculate the thermal energy required to convert 5 kg of ice at 0 degrees celsius to steam at 100 degrees celsius. (specific heat capacity © of ice = C of steam = 2100 J\Kg\K, specific heat capacity © of water = 4200 J\Kg\K, Latent heat of vapourisation = 2.3 X 10^6 J\Kg, Latent heat of fusion = 3.3 X 10^5 J\Kg

 

 

thanks...

 

 

I think this is how it is done :

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T.E to convert ice at 0'C to water at 0'C = ml_f

T.E to convert water at 0'C to water at 100'C = mS d :theta:

T.E to convert water at 100'C to steam at 100'C = ml_v

 

T.E = ml_f + mS d :theta: + ml_v

= 15.25 * 10⁶ J

 

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l_f = Latent heat of fusion = 3.3 X 10^5 J/Kg

S = C of Water J/Kg/K

l_v = Latent heat of vaporisation = 3.3 X 10^6 J/Kg

 

 

 

Don't know the function of - specific heat capacity © of ice = C of steam = 2100 J\Kg\K

 

I'm sure there's a mistake somewhere.