caseclosed Posted January 4, 2006 Share Posted January 4, 2006 What is the slope of the tangent line to the curve xy^2+5tan(xy)-2y+x=4 at the point (4, 0)? ok, I used implicit differentiation to find dy/dx then plug in those 2 points to find the slope of the tangent line but I don't know how to find the derivative of 5tan(xy). Link to comment Share on other sites More sharing options...
caseclosed Posted January 4, 2006 Author Share Posted January 4, 2006 I got - .0556 for my answer, found this site that gives derivative of tan(xy)=sec(xy)^2 * (x*dy/dx+y) can anyone show me how derivative of tan(xy)= that above in steps Link to comment Share on other sites More sharing options...
NeonBlack Posted January 5, 2006 Share Posted January 5, 2006 Use the chain rule to first you differentiate the tangent, times the derivative of the inside, using the product rule and differentiating y as a funtion of x. Link to comment Share on other sites More sharing options...
caseclosed Posted January 5, 2006 Author Share Posted January 5, 2006 nvm this topic, lol. I got integral and derivatives messed up, thought sec(x)^2 was the integral of tan(x). heh Link to comment Share on other sites More sharing options...
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