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Punnet Square

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when finding the genotype ratio of Aa * Aa

we could use binomial expansion (A+a)*(A+a) to get 1:2:1 ratio

but how do we find AaBbCc * AaBbCc ?

when finding the genotype ratio of Aa * Aa

we could use binomial expansion (A+a)*(A+a) to get 1:2:1 ratio

but how do we find AaBbCc * AaBbCc ?

Hm interesting observation. I expect it would be (A+a+B+b+C+c)*(A+a+B+b+C+c) unless there is something I misunderstand about the question?

I think you may want to use something called the multinomial expansion. Basically, the multinomial theorem says:

 

[math](x_1 + \cdots + x_k)^n = \sum_{\stackrel{n_1, \dots, n_k \geq 0}{n_1 + \cdots + n_k = n}} \frac{n!}{n_1! \, n_2! \cdots n_k!} \, a_1^{n_1} \cdots a_k^{n_k}[/math]

 

You can find out more about it at MathWorld.

  • Author

did it wrong. damn it. I found this online calculator, just gonna use that....

I thought it would but there seem to be some difference

I mean here is example

 

for Aa * Aa' date=' on the punnet square we write,

A a (on top) * A a (on side)

 

for AaBbCc * AaBbCc, we write

ABC ABc AbC Abc (on top) * ABC ABc AbC Abc (on side)

 

notice it is 3 letters at a time instead of 1 letter.[/quote']

 

Oh yes, very different I see... I really have not seen a solution for this, maybe Dave's link will work.

 

Are you saying that there are 4 different tops or 4 different columns? If the latter I expect the solution to still be represented by (ABC+ABc+AbC+Abc)*(ABC+ABc+AbC+Abc)

  • Author

fixed it, I forgot to add the other variations.

it would be this below

 

ABC ABc AbC Abc aBC aBc abC abc (on top) *

ABC ABc AbC Abc aBC aBc abC abc (on side)

Because the alleles assort independently, you just "layer it" (or whatever the actual math term is). In essence, to find the probability of, say AABbCC, you say there's a 1/4th probability os AA, a 1/2 probability of Bb, and a 1/4th probability of CC, so the total probability is 1/32. Repeat ad nauseam.

 

Of course, it can get lots more complicated, with linkage disequilibrium (where alleles *don't* assort independently), but that's a whole different mess.

 

Mokele

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