Capiert Posted July 12, 2023 Share Posted July 12, 2023 (edited) Proposal: If I could bend (=modify) Newton’s (3) laws ((in)to) the way I want for a consistent continuum, I would deal (mostly) with averages e.g. for (inverse_)time, distance, speed, momentum (& its squared) & mass*Force. Disclaimer: (0. (Some people might think,) What goes up must come down. It’s called the 0th(=zero_th) law because he(=Newton) didN’T invent it. Joke aside. ..But (otherwise) here..) (To be consistent, & thus rebose.) Preparation: The (average_)distance da divided by the (average_)time ta is the average_speed va=da/ta. (I have to (repeatedly) say that “average_” so often, (because (I try)) NOT to be misunderstood, if I were to (simply) say, (the average_) speed is d/t.) 1. The average_momentum moma=ma*va is a(n average_)mass ma (coefficient, factor) multiplied by its average_speed va. 2. To be consistent((ly) based) on the same basis, (then) the (average_)mass*(average_)Force ma*Fa=moma2/da is (simply?) the average_momentum squared moma2=ma2*va2/da (then) divided by the (average (accelerated) traveled) distance da. (That would be my substitute for mass*Vis_viva &/or (what seems to me) the (ERRORFUL=misguiding=misleeding, (interactive) work_)energy (concept WE=F*d which is wrongly (proportioned, to only) force F multiplied by distance d & (thus) needing an extra mass m factor as Ewert proposed 1996.) Or the kinetic_energy_(difference, concept) KEd=m*vd*va which uses the speed(_difference) vd=vf-vi for the final_speed vf minus the initial_speed vi. moma2/da=ma*(ma*aa) is the (average_)mass ma multiplied by the average_Force Fa= ma*aa of a(n average_)mass ma multiplied by the average_(linear_)acceleration aa=va2/da. moma2/da=ma*Fa which I would love to simply call mass*Force(_average). 3. [Newton’s 3rd law of] repulsion (of((=for) the average) mass*Force) explains how colliding (accelerating) masses are equally proportioned. (moma12/da1=ma1*Fa1)+(moma22/da2=ma2*Fa2)=0. Again (ma1*Fa1)+(ma2*Fa2)=0, ma*Fa=ma2*aa (ma12*aa1)+(ma22*aa2)=0 (moma12/da1)+(moma22/da2)=0. Note: 2b. (=To_be) A general average_acceleration aan=van/dan-1 could be based (up)on the “exponential” average_speed van= aan*dan-1 (for any n>1, e.g. beyond 1) which is an(y) average_acceleration (even NON_linear kinds=types), where “a” is just a symbol ((only) meaning (a=the) motion; NOT necessarily acceleration!). “n” is just (for) the order of motion where 0 does NOT move? 1 is the (average_)speed (=NO_acceleration) 2 is the average_linear_acceleration 3 is the average_NON linear_acceleration of the 1st order 4 is the average_NON linear_acceleration of the 2nd order etc. n<1 Exponent n values below(=less_than) 1, decelerate. Edited July 12, 2023 by Capiert Corrections Link to comment Share on other sites More sharing options...
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