boogerscout Posted September 15, 2005 Share Posted September 15, 2005 Hi all! I'm really stuck on this problem. I have a v vs t graph showing car A at constant acceleration = 0 m/s2 (horizontal line) with a v=8m/s and car B having a constant acceleration of 3m/s2 (found using slope of the line) with average velocity equal to 6m/s (found by (v2-v1)/2). Here's the question: At t=0, both cars are at x=0. Estimate (a) where and when they meet again and (b) their velocities when they meet. 1. I was told that using acceleration I can find x, but I'm thinking I have to do an integral to do this. Is there another way? I was also told this could be solved using a quadratic equation, but I don't understand how. Can anyone give me an idea how to solve this? I don't want the answer (although it may be nice to check my work against), but I would appreciate any input on where to begin.. Thanks in advance. Link to comment Share on other sites More sharing options...
Klaynos Posted September 15, 2005 Share Posted September 15, 2005 if you use: s=ut+0.5*at^2 (u is the initial velocity) Equate for both the systems so: u1t+0.5*0*t^2 = u2t+0.5*3*t^2 You can calculate the time, and anything else you need from there... Link to comment Share on other sites More sharing options...
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