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Regular expression to NFA-confusing regular expressions-:

shivajikobardan
in Computer Science

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R=(01+010)*

For it I made the below nfa which i believe seems correct. Plus the tutorials that I am following also make sure it’s correct. Q0 is initial state(forgot to mention in figure).

GUZlDA7_UjNWlcNx76e1xHOYhNjYBzbDMnP9qBnMjL8ux_Ntz3SSVIcw-VfMR6jbFlbxYG3nx6ccd2gWObG2hXnmXLE14mKI4PtFf4GtDc_PgenECvC_h_m9Yrbrg99hHZh258F9

 

R=(01)*+(010)*

 

But idk how to convert this to NFA

What will be languages accepted by this NFA? Won’t it be the same as the above one? 

 

(for some different question)

I got small hint about this. It was to add epsilon transition, but I don’t understand the need for it.

naVKgIC_8oj_v6TLAyjAhdOlLEpr4jsUAiYNw59d-2LifF5scOxn7rBw0AwCvmDwtFMZtv-s7DfXZAkt5OTNOksg7PNgzhEhyEXJ1JRmtN4nIELpWrJCIUaKA7uvrJatk6oTbd2k

Source-: https://www.cs.wcupa.edu/rkline/fcs/nfas.html

 

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