Dhamnekar Win,odd Posted April 1, 2022 Share Posted April 1, 2022 (edited) In hypergeometric distribution, n= population of n elements, r = sample size, n1 = elements recognized as having some defined criteria, n2 = n - n1 = remaining elements other than n1 . We seek the probability qk such that the sample size r contain exactly k recognized elements provided [math]k \geq 0, k \leq n_1 [/math] if n1 is smaller or [math] k \leq r[/math] if r is smaller. In such a case the probability [math]q_k =\frac{\binom{n_1}{k}\binom{n- n_1}{r - k}}{\binom{n}{r}} \tag {1}[/math] Now, I want to calculate n=8500, n1 =1000, r = 1000, k = 0 to 100. Inserting these values in (1), calculation of summation is very difficult. In such case, how can I use normal approximation to binomial distribution to find qk ? Do you have any clue or hint? Edited April 1, 2022 by Dhamnekar Win,odd Link to comment Share on other sites More sharing options...
Genady Posted April 1, 2022 Share Posted April 1, 2022 I don't know about the normal approximation in this case, but Excel has HYPGEOMDIST() function... Link to comment Share on other sites More sharing options...
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