Gemm94 Posted April 24, 2021 Share Posted April 24, 2021 Please help me the following equation, we need to calculate X relative to the other: \begin{equation} \tan{(2X-\phi_0)} = \frac{\rho\sin{\phi-a\sin{X}}}{\rho\cos{\phi}-a\cos{X}} \end{equation} Thank you very much! Link to comment Share on other sites More sharing options...

Country Boy Posted April 26, 2021 Share Posted April 26, 2021 (edited) What does "relative to the other" mean? What "other"? [math]tan(\alpha- \beta)= \frac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}[/math] so [math]tan(2X- \phi_0)= \frac{tan(2X)- tan(\phi_0)}{1+ tan(2X)tan(\phi_0)}[/math]. By the same formula [math]tan(2X)= tan(X- (-X))= \frac{2tan(X)}{1- tan^2(X)}[/math] Edited April 26, 2021 by Country Boy 1 Link to comment Share on other sites More sharing options...

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