Gemm94 0 Posted April 24 Share Posted April 24 Please help me the following equation, we need to calculate X relative to the other: \begin{equation} \tan{(2X-\phi_0)} = \frac{\rho\sin{\phi-a\sin{X}}}{\rho\cos{\phi}-a\cos{X}} \end{equation} Thank you very much! Link to post Share on other sites

Country Boy 69 Posted April 26 Share Posted April 26 (edited) What does "relative to the other" mean? What "other"? [math]tan(\alpha- \beta)= \frac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}[/math] so [math]tan(2X- \phi_0)= \frac{tan(2X)- tan(\phi_0)}{1+ tan(2X)tan(\phi_0)}[/math]. By the same formula [math]tan(2X)= tan(X- (-X))= \frac{2tan(X)}{1- tan^2(X)}[/math] Edited April 26 by Country Boy Link to post Share on other sites

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