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I need some help with calculus.

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Hello. This the problem: The population of Booneville increases at a rate of r(t)= (3.62)(1+0.8t^2) people per year, where t is the time in years from 1970. The population in 1976 was 726. What was is it in 1984?

I' ve been trying integrating and then evaluating the integral at t=8 (8 years, 1984-1976=8). The answer must be \approx 3195. I want to learn this because I saw the next problems in my textbook are similar to this one. It might be silly, but any help is welcome.

Thank you.

If you did it and got ~ 3195.323, then it looks like you did it correctly.

Or are you just referencing the answer  known from a solution book?

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