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David M

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  • Location
    Atlanta, GA
  • College Major/Degree
    MS - BioOrganic Chem, PhD - Organic Chem

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  1. I am aware that it's just a crystallization. But the fact remains that googling the term 'hot ice' will net a lot of links showing how to do the demo. I'm simply stating a fact and not offering my opionion...
  2. Originally posted by hermanntrude: Also you can make your own sodium acetate and supersaturate it. the resulting solution will crystallise rapidly (in seconds), which can be fun. youtube "sodium acetate" and you'll see more... I agree that this is a pretty cool experiment. You can also find out more by google-ing 'hot ice'...
  3. hey!

    this forum is pretty good methinks :)

  4. It could be that your TMS ether is unstable on silica gel and, therefore, decomposes when you are TLC-ing your reaction mixture. TMS ethers are fairly easily hydrolyzed and phenolic ethers even more so. I suggest taking an NMR of a reaction aliquot...
  5. Hi Lan, Let me see if I can help you. Farmboy was on the right track. First, the molecule (E)-4-octene is the hydrocarbon that is 8 carbons long and has a trans double bond between the C-4 and C-5 carbons. In other words, it's a symmetrical trans olefin with two n-propyl groups on each side of the double bond. The best way to synthesize a trans double bond is by performing a stereoselective reduction on the corresponding triple bonded compound, in this case, oct-4-yne. Two condtions that should work are the dissolving metal reaction conditons (Na metal / liq. NH3, -78 degrees C) or a lithium aluminium hydride reduction (LAH, THF). By the way, you could also try to get the olefin by doing a hydrogenation of the alkyne but it's very difficult to stop the reduction at the alkene state unless you use a poisoned catalyst. However, the problem with using a posinoned catalyst such as Lindlar catalyst is that the cis olefin is favored/formed. The next part of the syntheis requires figuring out how to make oct-4-yne from compounds of 3 carbons or less. The best way is to do that is to react 1 equivalent of acetylene with 2 equivalents of propyl bromide in the presence of a strong base such as n-butyl lithium. If you add 2 eq. of BuLi to 1 eq of acetylene, you will get bis lithium acetylide [Li-C(triplebond)C-Li] which will undergo SN2 displacement of the alkyl halide to give you the desired alkyne... Hope this helps!!!
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