plerza

So I was bored for a bit at work today & decided to do a little math. I will admit, I trusted KGB to give me the average volume of a human body, which was off by 10 to the -15th. Then, when I 'corrected' their math, I was off my 10 to the -1th, so this is the revamped version. I hope it is all relatively accurate now. Measurable Theoretical Breakdown ofthe Universe: A Paper for Amusement by Pete Lerza 11/10/2012 I’ve done all mathematics with fairlyloose approximations. The purpose of this is not for scientific accuracy, butfor a general understanding of a theoretical size of the Universe. The Names ofthe Large Numbers are in the American Standard form [then the European StandardForm] but not SI prefix or Greek-based forms. I decided to determine whatpercentage of the theoretical volume of the Universe that Earth consumes, thenwhat percentage of the theoretical volume of the Universe that you consume. To write a number in scientific notation: Put the decimal after the first digit and drop the zeroes. Inthe number 256,000,000,000 The coefficient will be 2.56 To find the exponent count the number of places from the decimal to the endof the number. In 256,000,000,000 there are 11 places. Therefore we write 256,000,000,000as: 2.56 x 1011 To begin, we assume that the Universeis 13.7 billion years old & that it takes light 3 x 10-9 s totravel one meter. We then convert the age of the Universe into seconds, dividethe age of the Universe in seconds by the amount of seconds it takes for lightto travel one meter & have an approximate radius of the Universe in meters. (13,700,000,000 years)(365 days)(24hours)(60 minutes)(60 seconds) = 4.32 x 1017 s {432,000,000,000,000,000 s} {432quadrillion [billiard] seconds} 4.32 x 1017 s is the ageof the Universe in seconds (4.32 x 1017 s) / (3 x 10-9s) = 1.44 x 1026 m or 1.44 x 1023 km 1.44 x 1023 km is the TheoreticalRadius of the Universe A Diameter is determined bymultiplying the Radius by 2 The Theoretical Diameter is 2.88 x 1023km We know the Universe is not a Circleor Sphere, but we do not have enough information to calculate the dimensions ofan ellipse or elliptical sphere, so we will practice under the theory of whichthe Universe is a Circle, which should give us approximately the samepercentages at the end. Circumference of a Circle = x Diameter (2.88 x 1023km) = 9.05 x 1023 km {905,000,000,000,000,000,000,000 km}{905 sextillion [trilliard] kilometers} 9.05 x 1023 km is our TheoreticalCircumference of the Universe Area of a Circle = (1.44 x 1023 km)2 = 6.51 x 1046km2 {6,510,000,000,000,000,000,000,000,000,000,000,000,000,000km2} {65.1 quattuordecillion [septilliard] squarekilometers} 6.51 x 1046 km2 isthe theoretical Area of the Universe Volume of a Sphere = (4/3)r3 (4/3)(1.44 x 1023 km)3= 3.98 x 1069 km3 {398,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,0000,000,000km3} {3.98 duovigintillion [undecilliard] cubickilometers} 3.98 x 1069 km3 isthe Theoretical Volume of the Universe Measurements in Miles: 1 km = 0.62Miles Radius: 8.9 x 1022 Miles Diameter: 1.79 x 1023Miles Circumference: 5.62 x 1023Miles Area: 4.05 x 1046 SquareMiles Volume: 2.47 x 1069 CubicMiles The given Radius of Earth is 6,378.1 km. Earth is a Sphere. Volume of a Sphere = (4/3)r3 (4/3)(6,378.1)3 = 3.46 x1011 km3 {346,000,000,000km3} {346 billion [milliard] cubic kilometers} The Volume of Earth is 3.46 x 1011km3 To determine what percentage of theUniverse is Earth, we divide the Volume of Earth by the Volume of the Universe.To divide numbers in Scientific Notation, we divide the coefficients, then subtract the exponents. (3.46x 1011 km3) / (3.98 x 1069km3) = (3.46 / 3.98) x 10 (11- 69)= 8.7 x 10-59% {0.000 000 000000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 087 %} {8.7octodecillionths [nonilliardths] of a percent} The Earth consumes 8.7 x 10-59% of the Theoretical Volume of the Universe The average given Volume of a Human Being is 6.93 x 10-2 m3 We know the Volume of the Earth &the Theoretical Volume of the Universe in kilometers, so to convert 6.93 x 10-2m3 to km, we divide by 1,000 = 6.93 x 10-5 km3 To determine what percentage of theEarth is a Human Being (You), we divide the Volume of You by the Volume of theEarth. (6.93 x 10-5 km3)/ (3.46 x 1011 km3) = 2.00 x 10-16 % {0.000 000 000000 000 2 %} {2 quadrillionths [billiardths] of a percent} You are 2.00 x 10-16 % ofthe Earth’s Volume To determine what percentage of theUniverse is a Human Being (You), we divide the Volume of You by the TheoreticalVolume of the Universe. (6.93 x 10-5 km3)/ (3.98 x 1069 km3) = 1.74 x 10-74 % {0.000 000 000000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 000 01 74 %} {174 trevigintillionths[duodecillionths] of a percent} You consume 1.74 x 10-74 %of the Universe’s Theoretical Volume Let me know your thoughts! Anything regarding details that I mentioned, was vague about or just totally missed, email me at plerza@live.com