When ammonium nitrate undergoes decomposition, only gases are produced, according to the equation
NH4NO3 > N2O + 2H2O
What is the total volume of gases produced at 546K and 1 atm pressure when 240g of ammonium nitrate undergoes the above decomposition reaction?
a) 9 x 22.4L b) 6 x 22.4L c) 12 x 22.4L d) 18 x 22.4L e) 3 x 22.4L
I got (a) but I'm not sure if i did it correctly...All I did was I found mols of H20 and mols of N20 which were 6 and 3, respectively. Then I added them to get 9 and picked a. I'm pretty sure this is totally wrong but I was trying to do PV=nRT but I didn't know how.