Prometheus83

look at the unix program sendmail

hehe, cheers. Its already been handed in, using x instead of u. Knowing my tutor I'll loose that mark for changing the letters, ah well.

Thanks for your help

Cheers

Hi,

Wondering if someone could point me in the right direction for this question. It is an assignment question, so I don't want the answer, just some help and point in the right direction. Heres what I have so far:

Find indefinite integral of: h(u) = sin^2 ( 1/6 u )

Now I'm presuming I need to use the double angle formula

cos(2x) = 1 - 2sin^2 x

to which I have:

sin^2 x = 1/2 (1 - cos (2x))

sin^2 (1/6 u ) = 1/2 (1 - cos (2 (1/6 u))

Therefore I get the answer

integral sin^2(1/6u) = integral (1/2 - 1/2 cos (2 (1/6 u )))

=1/2x - 3/2 sin (1/3 u ) + c

Is that anywhere close?

use approxamations?

pi = 3 etc?