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Prometheus83

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    5
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About Prometheus83

  • Rank
    Lepton
  • Birthday 10/27/1983

Contact Methods

  • Website URL
    http://www.cslingsby.com

Profile Information

  • Location
    UK
  • College Major/Degree
    HNC Engineering / Open University Maths degree
  • Favorite Area of Science
    Anything goes, but particually computer science.
  • Occupation
    Instrument Tech
  1. look at the unix program sendmail
  2. hehe, cheers. Its already been handed in, using x instead of u. Knowing my tutor I'll loose that mark for changing the letters, ah well. Thanks for your help
  3. Hi, Wondering if someone could point me in the right direction for this question. It is an assignment question, so I don't want the answer, just some help and point in the right direction. Heres what I have so far: Find indefinite integral of: h(u) = sin^2 ( 1/6 u ) Now I'm presuming I need to use the double angle formula cos(2x) = 1 - 2sin^2 x to which I have: sin^2 x = 1/2 (1 - cos (2x)) sin^2 (1/6 u ) = 1/2 (1 - cos (2 (1/6 u)) Therefore I get the answer integral sin^2(1/6u) = integral (1/2 - 1/2 cos (2 (1/6 u ))) =1/2x - 3/2 sin (1/3 u ) + c Is that anywhere close?
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