# Prometheus83

Members

5

## Community Reputation

10 Neutral

• Rank
Lepton
• Birthday 10/27/1983

## Contact Methods

• Website URL
http://www.cslingsby.com

## Profile Information

• Location
UK
• College Major/Degree
HNC Engineering / Open University Maths degree
• Favorite Area of Science
Anything goes, but particually computer science.
• Occupation
Instrument Tech
1. ## Outgoing server!

look at the unix program sendmail
2. ## Integration help

hehe, cheers. Its already been handed in, using x instead of u. Knowing my tutor I'll loose that mark for changing the letters, ah well. Thanks for your help

Cheers
4. ## Integration help

Hi, Wondering if someone could point me in the right direction for this question. It is an assignment question, so I don't want the answer, just some help and point in the right direction. Heres what I have so far: Find indefinite integral of: h(u) = sin^2 ( 1/6 u ) Now I'm presuming I need to use the double angle formula cos(2x) = 1 - 2sin^2 x to which I have: sin^2 x = 1/2 (1 - cos (2x)) sin^2 (1/6 u ) = 1/2 (1 - cos (2 (1/6 u)) Therefore I get the answer integral sin^2(1/6u) = integral (1/2 - 1/2 cos (2 (1/6 u ))) =1/2x - 3/2 sin (1/3 u ) + c Is that anywhere close?
5. ## how do i work out the area of a circle without a calculator?

use approxamations? pi = 3 etc?
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