UrgentHelp

Thanks for help !

I understand what your getting at. Whats the next step from that point. And no the acceleration is'nt constant. Btw i think you took down my force incorrectly. Mixed up the i and j ?

I dont understand how to split it down but since I have acceleration can I get that and sub it into s = ut + 1/2at^2 with the other values and solve for s ?

Ok i've tried this. F = ma F = ti - 6t^2j + 3k v = j + 2k mass = 4 kg ti - 6t^2j + 3k = (4)a ti - 6t^2j + 3k / 4 = a V = u + at j + 2k = 0 + (ti - 6t^2j + 3k / 4) 1 4(j + 2k) = ti - 6t^2j + 3k 4j + 8k = ti - 6t^2j + 3k = ti - 6t^2j - 4j + 3k - 8k = ti - 6t^2j - 4j - 5k

I think your suggesting integration. I dont understand integration but I can do differentiation. I can use F = ma if that would work ?

Honest answer is I dont know how to start on the question and Im just in desperate need of seeing a worked solution on it.

(a) A particle of mass 4 kg moves under a force: F = 6t^2i - tj - 4k in Newtons. Assuming that the particle is initially at the origin with velocity v = i + k in m/s, find its position after 1s. (b) A ball of mass m travels with velocity 3 m/s and collides with a second ball with mass 2m at rest. After the collision the 2m ball moves with speed 1 m/s in a direction 60degrees to the original direction of the ball m. (i) What is the final velocity of the ball m ? (ii) What is the angle between the paths of the two balls after the collision ? If you could answer and explain how to do either or even both of these it will possibly save me from failing an exam tommorow . Hope you can help, Thanks !