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DeanK2's Achievements


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  1. I have done the particle in a sphere with QM, but am trying to contrast it with the classical description.
  2. I would like to set up a statistcal equation to describe the probabiliity of where a particle can be found in a sphere of zero potential, and the collisions betweeen the wall and particle is perefctly elastic.
  3. The three most abundant elements: 1.) Hydrogen 2.) Helium 3.) Lithium (universe)
  4. Electronegativity is the ability of an atom to attract a pair of electrons in a covalent bond. The nuclear charge and the atomic radius determine the electronegativity - the larger the nuclear charge, the more it will attract a bonding pair of electrons. The smaller the atomic radius, the greater the attraction between the nucleus and the bond electrons. On descending a group, the effective nuclear charge on an atom remains the same, but the size increases. Therefore the top member is more electronegitve, as it is smaller and attracts the bonding electrons more. Therefore, an electronegative atom would not be readily oxidised. Therefore an electronegative metal would be low down in the electromotive series. The electromotive series begins with the metal most easily oxidized, i.e., the metal with the greatest electron-donating tendency, and ends with the metal least easily oxidized. The tendency to be oxidized is not an absolute quantity; it can only be compared with the tendency of some other substance to be oxidized. In practice, the tendency to be oxidized, called the oxidation potential and expressed in volts, is measured relative to a standard hydrogen electrode, which is arbitrarily assigned an oxidation potential of zero. ELECTROMOTIVE HAS NOTHING TO DO WITH ELECTRONEGATIVITY FOR A REFERENCE OF VALUES: BUT EACH CAN BE EXPRESSED BY EACH OTHERS DEFINITION.
  5. Enviroment? Sealed? If so, you can phosphorous to remove the oxygen - it will not react with water or corrode stainless steel. Unfortunately problematic element - reacts vicously and spontaneously with air - have not actuallly handled it myself so revise safety. Fire. Oxidised to [math]P_{4}O_{10}[/math].
  6. Laminar flow - imagine a Liebig condenser http://www.efm.leeds.ac.uk/CIVE/CIVE1400/Section4/laminar_turbulent.htm provides simple example for equation.
  7. DeanK2

    without trig

    [math]BDC=180-8x[/math] [math]ABD=180-12x[/math] [math]0<x< 15[/math] [math]20x+ABD+BDC=360; =>...ABD+BDC > 60...if...0<x<15[/math] With the limits above, x can be found. A simple logarithm would suffice.
  8. The above is sufficient, yet also the root itself must be differentiable.
  9. [math]x^4=x^2y-y^3[/math]; implicit differrentiation and the product rule must be applied. Solve as stated.
  10. Wiles proof that [math]x^n+y^n=z^n, n>2 --> xyz=0[/math] Lebiniz and his most elegant equation [math]pi/4=1-(1/3)+(1/5)-(1/7)....[/math]
  11. Revise phase equilibria and Raoults law. [math]P=P^ym[/math] P is the vapour pressure of the solution, [math]P^y[/math]=vapour pressure of the pure solvent [math]m[/math]=mole fraction of solvent in the solution. Use [math]pV=nRT[/math] to find kelvin.
  12. Not entirely sure that the question would contain the words incomplete dominance as it does not exist. The actual term is co-dominance - extremely important this is used, as in a question; the use of incomplete would loose all marks. Co-dominance is the term used to describe the way two DIFFERENT alleles are expressed in the phenotype of an organism. Consider these crosses in a punnet square: R-dominant, r – recessive R produces white flowers. r results in blue flowers r R R Rr RR r rr Rr It is clear that the genotype with a capital R would have white flowers. Approximately 3:1 would have white: blue flowers. The punnet tables are not easy to show, but top row of each one should be moved over by a place. Now, in co-dominance, there is actually no dominance. Both alleles are equally expressed: r R R Rr RR r rr Rr So, RR would be white, and rr would be blue. Rr would be a light blue - because neither allele is dominant over the other, the heterozygous genotype has its own phenotype. However, since the original phenotype has been unaltered and remains, they still obey Mendel's law of segregation. It is only the phenotype that appears to have undergone "incomplete dominance", and this is a common mistake. Co-dominance affects blood groups - that is why the AB group can be present - the A or B allele is not dominant, so both antigens are produced.
  13. The later questions require a slight knowledge in the dihybrid principle (Mendel) and co -dominance. If you need an explanation of both, with punnet squares, simply post.
  14. This is correct and balanced: CH3(CH2)2CH2OH + 6O2 ------------> 4CO2 + 5H2O
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