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elfmotat

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Posts posted by elfmotat

  1. Are all particles considered to be an excitation on the same field?

    Or is there an electron field for electrons,a positron field for positrons

    a photon field for photons,a gluon field for gluons etc?

     

    With energy being transferred from one field to another?

     

    The latter. You can just think of different particles as being excitations in different fields, and those fields can interact with each other according to some rules we call "laws of physics."

  2. This approximation may be acceptable at present, when most of the volume of the universe consists of voids, but it becomes grossly inadequate when we go back in time, e.g., to z=10 (of the most distant galaxy that has been observed). The scale factor a(t) was then roughly 0.05 and the volume of the universe about a factor of 10^-4 smaller than it is now. There was not much room for expanding voids then.

     

    I don't think you understand what the word "homogeneous" means. The universe was still homogeneous when it was younger, it was just denser. It has nothing whatsoever to do with the scale factor.

     

    In order to convince me that I am wrong, it won't do with arguments that presuppose any of the rejected things to begin with.

     

    So you won't accept approximations because... you don't like approximations? Are you waiting around for an exact solution to the EFE's for our universe? Good luck with that. In the mean time, the rest of us will be making progress with our useful approximations.


    My point is is very simple: In my understanding, the universe cannot ever have had a volume smaller than that of the regions that are gravitationally bound at present.

     

    It's hard to respond to arguments that don't make sense. Why in the world would you think this? What led you to this thought?

  3. Can this happen outside the relativistic horizon?

     

    Like a Rindler Horizon? Sure, but you'll never be able to interact with them because they're beyond the horizon. You'll probably get interesting effects from the horizon itself, like Hawking radiation. I am by no means an expert on this though, so I may not be as helpful as I'd like.

  4.  

    OK. The stretching rubber sheet represents the expanding universe as described by Friedmann, Robertson-Walker, the ΛCDM concordance model, etc. These models have been derived on the basis of GR, assuming that the mass of the universe is distributed uniformly. They assume that there are no coherent objects (neither small ones nor larger ones, such as galaxy clusters etc, which probably house nearly all the matter in the real Universe). Further, they describe the possible evolution of the universe in a system of reference that is not itself affected by this evolution, like that in which a coin on the rubber sheet is static. However, coins on the rubber sheet are not within the universe. If anything, they represent separate, metrically static worlds outside the universe.

     

    In order to model the actual Universe, to which there is no outside, it would be necessary to have the coins embedded within the rubber sheet. But this would make it clear that the Universe could never have been smaller than the volume of the coins and that the mentioned models and the big bang are grossly unrealistic.

     

    Because the FLRW metric is obviously just an idealization which makes for useful approximations, just like most anything else in physics. At large enough scales the universe is approximately homogeneous, meaning the FLRW metric approximates our universe at large scales.

    You also shouldn't take analogies too seriously: space isn't 2-dimensional either! I only provided the analogy because it makes visualization easier, which is sometimes helpful for people who aren't well-versed in this stuff.

  5.  

    Yes I improved the setup by relaxing the simultaneity requirment, but I didn't say any such thing as you suggest about separation.

     

    That d is never zero is the one thing I have affirmed in each and every post.

     

    Ah, okay, I understand. Our disagreement was coming from what we were using [math]d[/math] to represent. I was taking it to mean their separation when they are destroyed, while you were using it only as an initial separation so that initial P.E. can be calculated. That makes sense.

     

     

    Every experiment ever conducted, thought or actual has always been selective.

    Clearly the trick is to realise what matters and what doesn't.

     

    However I am not trying to rewrite physics, merely explore the consequences of something we both know has been achieved in the lab, viz the anihilation of a charged particle by its antiparticle.

    I am sorry I do not have Caltech's ability to produce fancy (or even simple) video, but relative motion is relative motion so either the charge or the field (or both) could be moving.

     

    In this nice video from Caltech about the expanding relativistic discontinuity about a moving charge, imagine the expanding bubble is empty because the charge has been extinguished by antimatter.

     

    Prior to the anihilation the field is as shown, but then it is wiped out by the expanding empty bubble.

     

    Is this a viable model?

     

    http://www.tapir.caltech.edu/~teviet/Waves/empulse.html

     

    I have no problems with this setup in terms of it violating any physical laws, but it is a bit fuzzy. In classical physics particles can never be created or destroyed -- you need QFT for that, with the introduction of creation/annihilation operators. The problem being, at this level all interactions consist of some sort of particle exchange. I.e. the charge doesn't really generate a classical EM field, it generates a bunch of virtual photons, a collection of which will act like a classical field at larger scales.

     

    As for where the energy goes, it can remain in that field or be transferred to other fields -- for example e⁺ e⁻ γ γ converts all the mass/kinetic/whatever energy the electron/positron field had into two EM field excitations, called photons. Energy is conserved in all interactions like this because there is a 4-momentum conserving Dirac Delta Function in the Feynman rules for calculating amplitudes.

  6. It's difficult to discuss in the face of overdramatic language.

     

    I'm certainly not trying to be dramatic, especially not overly so. If my bluntness offends then I apologize. The scenario makes for an inconsistent thought experiment because you are picking and choosing which physical laws you do/don't want to ignore, and some them can't be ignored in any meaningful or consistent way. The continuity equation for charge conservation is absolutely fundamental, and removing it means that the EM field is no longer a gauge field -- which means the entire theory of EM would have to be re-written for your question to make sense. You were also trying to remove locality, which is completely contrary to the point of using field theory in the first place.

     

    Two charges are separated by some distance d, measured in any way you choose, are destroyed sequentially by being brought into contact with their antiparticle.

     

    What you appear to be denying is that physics forbids you to ever destroy any charged particle this way, under any circumstances.

     

    This, of course, does not conform to observed reality.

     

    You changed the setup of your thought experiment. You originally said the charges would be destroyed while separated, and now you're saying they are brought together. The latter makes sense -- the former doesn't.

  7. Hmm, let me see

     

    I do believe I specified that the two charges are not in relative motion, ie d is constant, in the first part of post#1

     

    Since there is no relative motion between them the exact centre point will be the same in all reference frames.

     

    Not that it really matters, the experiment would still offer a question even if one was destroyed before the other.

     

    The second part of post#1 dealt with the situation where they are in relative motion, although the issue still remains

     

    Say we're in a reference frame where the charges are separated by distance [math]d[/math] and both are destroyed simultaneously, i.e. [math]\Delta t = 0[/math]. If we boost to a frame moving at [math]v[/math] w.r.t. the charges, parallel to them, then the difference in time between when each charge was destroyed in this new frame will be:

     

    [math]|\Delta t'| = \frac{vd/c^2}{\sqrt{1-v^2/c^2}} \neq 0[/math]

     

    The scenario you propose violates physics, which is why I can't use physics to explain what happens.

  8. Sure, in the real world, the ruler (= the meter) does not expand, but to my understanding this blatantly contradicts the claim that the metric space expands.

     

    Then, what is the reason for ascribing the expansion of the universe to an expansion of metric space?

     

    Sure, but in order to stay the same size in their non-expanding metric space, meter rules need to contract in the assumed expanding metric space (which stays the same size in comoving coordinates).

     

    Put a coin on a rubber sheet and stretch it. The space of the sheet is expanding, but it is not nearly enough to overcome the molecular bonds in the coin and rip it apart. This simulates galaxies, clusters, and other gravitationally bound objects. The force of expansion is not enough to overcome their gravity.

     

    If you put two coins on the sheet and stretch it, the coins will move apart from each other. This is because the coins are not bound to each other. It simulates two galaxies which are very far apart, such that their gravitational interaction is too small to overcome expansion. Also notice that the coins on the sheet reproduce Hubble's Law: if they are twice as far apart they will move twice as fast away from each other.

  9. No I disagree post#1 was correct.

     

    [math]d \ne 0[/math]

     

     

    But I explained why this wouldn't work in my first reply. If the charges are separated by finite distance then they cannot be simultaneously destroyed in all reference frames. If the events are simultaneous in one frame then they necessarily won't be in other frames. That means one charge would be destroyed before the other, violating charge conservation.

     

    The only way for charges to be created/annihilated is with equal/opposite charges at interaction vertices, i.e. single points. All interactions must be local.

  10. (But you actually said time and space are quantized. (no 'if'). So even if your other statements didn't imply that, do you have a citation for accepted physics that says that time and space are quantized?)

     

    I was a biology major, for god's sake. But:

    1) "Introduction of a quantum of time(chronon) and its consequences for quantum mechanics", Roy A. H. Farias, Erasmo Recami, 27 Jun 1997, Cornell University Library

    2) Entry in Wikipedia, Quantum Spacetime> "...the concept of 'quantum spacetime' is a generalization of the usual concept of spacetime..."

    3) "Quantum Time", Mark Lawrence, July 13, 2011

     

    Agreed, these are not "citations", I shouldn't have said space-time IS quantized, but some people a whole lot smarter than I seem to think so. Also, M-Theory, (which I do not accept), the cutting edge of physics (or metaphysics, take your choice), certainly deals with the quantization of space-time, tho I truly can't wrap my brain around strings and 26 dimensions.

     

    Those are theoretical models, some of which have problems, and none of which are accepted physics.

  11. elfmotat I see no simultaneity issues with antimatter annihilators in a thought experiment.

    However I am sorry that I should have allowed the destruction apparatus in the thought universe.

     

    So pointing such issues out is how an idea develops.

     

    There's no problem, as long as all such interactions take place at a single point -- i.e. the distance d in your OP must be zero.

  12. I understand that, but the fundamental idea does have mathematical evidence to support it. The work was done by a fairly well known theoretical physicist, although it has not been peer reviewed. I came up with the idea independent of his theory, and I have expanded on the idea much further. I can see where it fits many things in nature.

     

    Isn't that what science is all about?

     

    I don't know what your idea was or which thread you're talking about. I was just explaining why posts are usually moved to the trash can.

     

     

    I'm not sure what you mean by "objective to discuss".

     

    Something along the lines of, "if my idea is correct then we should expect to see a value of X upon measuring such and such a quantity." Or, "this fits known data, as shown here." Something to tell us whether or not your idea is wrong, objectively.

  13. Please read the Speculation section's rules. Rule #1:

     

     

    The Speculations forum is provided for those people who like to postulate new ideas in the realm of science, or perhaps just make things up for fun. Whatever the case is, this forum is not a home for just any science-related idea you have. It has a few rules:

    • Speculations must be backed up by evidence or some sort of proof. If your speculation is untestable, or you don't give us evidence (or a prediction that is testable), your thread will be moved to the Trash Can. If you expect any scientific input, you need to provide a case that science can measure.

     

    This is a science forum. If there is nothing objective to discuss then we aren't doing science.

  14. The speed of an electron in an atom is key...

    ... in combination with the immense speed of the electron, ...

     

    The "speed" of the electron is not well-defined in atoms because they are not in eigenstates of the velocity operator. The best you can really do is an order-of-magnitude calculation:

     

    [math]\frac{mv^2}{2} \sim \frac{e^2}{4 \pi \epsilon_0 r}[/math]

     

    [math]mv \sim \hbar / r[/math]

     

    so:

     

    [math]v \sim \frac{e^2}{4 \pi \epsilon_0 \hbar c} \, c = \alpha c \approx \frac{c}{137}[/math]

     

    This is not a very large fraction of the speed of light. I.e. electrons do not really have "immense speed" in atoms, which is why non-relativistic quantum mechanics works so well.

    Due to the field between the proton(s) and electron(s) in combination with the immense speed of the electron, it creates vortexes within its atom.

     

    What field? What do you mean by "vortexes (sic)"?

    These vortexes are expelled from the atom in any and every direction probably at about the speed of light.

     

    What do you mean by "probably"? That sounds very vague. Vague theories are not scientific.

    When a gravity vortex pass threw another atom the field between the proton(s) and electron(s) of that atom gets distorted a little.

    The best way to describe the distortion is to compare the gravity vortex with a tornado. A tornado sucks in air one side and expel it the other. The gravity vortex does the same with the field.

    This tiny distortion makes the atom shift the parts of the atom a little bit in the direction where the gravity vortex came from

    No speed is gained or lost of the gravity vortex when it passes threw the atom.

     

    This is all rather vague as well. It's hard to comment on "theories" which are not well-defined or precise. This is why math is important.

    If so, I’m a strong NOT believer of the Big bang theory.

    In my view is a too easy solution to explain the un-explainable.

     

    Beliefs should be based on evidence. Apparently you don't agree? I can't argue with someone who does not take seriously the scientific method.

     

    “Or that gravity will affect the path of light?” No, don’t think so, maybe in extreme cases (extreme like black holes)

     

    Except we know for a fact that it does. This was demonstrated in 1919 with the original Eddington experiment to test General Relativity.

  15. But im asking about the moment of impact...an event horizon...at that moment, all the physics it took to get there dont matter...we have an impact with direction and force....if we do this in a vacuum, are there any other forces effecting that reaction?

     

    I know that I, along with at least one other person (Strange I believe), already stated in this thread that nothing special happens at the event horizon. There is no "impact." You would pass right through without noticing a thing. Passing through the event horizon just means that you would have to move faster than light to escape.

     

    It's like a boater in a river approaching a waterfall -- the closer he gets to the edge, the faster the water flows. Eventually, when he gets close enough, the water flows faster than the boat's top speed -- he has passed a point of no return and will inevitably fall off the edge of the waterfall. Nothing special happens at this point, just like nothing special happens at the event horizon.

  16. Thanks again for the response, but the whisky has flowed too freely to answer tonight.

     

    I will be thinking again in the morning, but your equations implied that charge is time independent and that all the charges that ever were in the universe were created all at once (how?) and cannot be uncreated.

     

    Total charge is indeed time-independent, but that doesn't mean charges can't be produced in interactions. γ + γ → e⁺ + e⁻, for example, produces two charged particles where previously there were none. Charge conservation requires equal and opposite charges be created/annihilated in any interaction. As for why there was more matter than antimatter created at the big bang, that remains a mystery :) .

  17. For people who are too comfy inside the box, it is obviously unsettling to see some out of box stuff. All I am suggesting is that some of the branches of science today have become 'unscientific'. Let's focus on this topic. If you have proof that can lead to validating or invalidating this idea, please post it here, otherwise just treat this topic as garbage and pass by.

     

    Assertions made without evidence can be dismissed without evidence. Do you have any to support your claims or not? If not then there is no topic to focus on.

  18. Good science starts that way, sometimes. i.e. it was started by 'ludicrous' idea and proved/disproved by people who had more time than what they know how to spend. Thinking out of box is my job.

     

    Good science starts with evidence, of which you have none. Thinking out of the box is fine as long as you don't bend facts to fit your ideas, instead of the reverse. Starting a topic based on an out-of-the-box idea is also fine, if you have evidence.

     

    What's not fine is starting a topic based on an out-of-the-box idea with zero supporting evidence, being too lazy to look for it yourself, and expecting others to do your work for you.

  19. You sound awfully like my friend Alan M. I appreciate his scientific rigor. But what I want is to get something new, interesting or helpful from a debate.

     

    So let me get this straight: you post a thread based on a ludicrous proposition for which you have absolutely zero evidence, and you expect us to find the evidence for you?

     

    Sorry, but I think we all have better things to do with our time.

  20. That is what interests me.

     

    I think you will find the others are possible, at least in a thought experiment.

     

    I did not say there would not be consequences, but to just dismiss it out of hand is too slick and simplistick.

    But thank you for replying anyway.

     

    I don't think I agree. The point of a thought experiment is to gain insight by imagining a physical scenario which is, in principle, possible. I don't know how to answer this question meaningfully because it is simply not possible. You're proposing a different set of physical laws which are incompatible with the laws we know govern nature. I.e. this thought experiment is not self-consistent.

     

    The energy of any field is given by its stress-energy. If you know the field Lagrangian then you can find the stress-energy with a variational derivative w.r.t the metric:

     

    [math]T^{\mu\nu} \equiv \frac{2}{\sqrt{-g}} \frac{\delta ( \mathcal{L} \sqrt{-g})}{\delta g_{\mu \nu}}[/math]

     

    In particular, the stress-energy of the EM field in flat spacetime is (in appropriate units):

     

    [math]T^{\mu\nu} = F^{\mu \alpha}F^{\nu}_{~\alpha} - \frac{1}{4} \eta^{\mu \nu}F_{\alpha \beta} F^{\alpha \beta}[/math]

     

    where F is the electromagnetic field tensor. This gives you the stress-energy of the EM field at any point in spacetime. I.e. if you pick a point and plug in the value of the EM field at that point, the above equation will tell you the energy/momentum density of the field there. Energy can be found by integrating T00 over 3-volume. The dynamics of T are governed by the dynamics of F. The continuity equations [math]\partial_\mu j^\mu = 0[/math] and [math]\partial_\mu T^{\mu \nu} = 0[/math] explicitly forbid the scenario you suggest. The dynamics of the field energy in valid physical scenarios are given by the prescription above.

  21. This scenario is not possible for a number of reasons:

     

    • Pressing "nuke one" violates charge conservation. If the two charges are not exactly equal and opposite, pressing "nuke both" violates charge conservation.
    • Even if they are equal and opposite it still violates local charge conservation. Say we press the "nuke both" button in a reference frame where both charges are at rest. The charges will be simultaneously destroyed. In another reference frame the events will not occur simultaneously, meaning for a finite period of time charge conservation was violated.
    • The scenario violates both local and global energy/momentum conservation.

     

    It's hard to use physics to describe scenarios that violate physics. As for where the energy of a field is stored, it is stored locally. Every field has a stress-energy which can be easily calculated from the field Lagrangian.

  22. I do see that...Yknow, when i look at SOME of the equations, the math isnt that daunting at all, but all the terms! I need to know the terms...IS there a good listing of all the terms in oneplace so I can just start memorizing them?

    3d1397d2ec41e24c1dfae61b101c13c9.png.

     

    Terms are not so important. Knowing the name of something is not the same as knowing something. (Another Feynman video.) You'll learn the terms over time, in their proper context, by reading textbooks or lecture notes -- the same way you learn interesting vocabulary words by reading books. Memorizing things is almost always a bad idea, as it does not really contribute to any meaningful understanding.

     

    What's important is understanding the math, what it means, and how to extract information from it. For example, the equation you posted above is a statement of local energy-momentum conservation. It means that energy/momentum cannot be locally created or destroyed.

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