azazel2113

Sorry for that guys,we do go to the same school and were pulling an all nighter review before a test. On this question, I did not know she had posted the work (probably due to lack of sleep) so I posted it. Won't happen again.

Hello, I need help with a problem that involves drawing structures. The question is Compound A with a molecular formula of C6H10 decolorizes Br2 and produces a precipitate when reacted with permanganate solution. Hydrogenation with H2 over Pd/C produces B with a formula of C6H12. Reaction of A with peroxyacetic acid produces C, which is highly strained. Hydration of C produces D. Reaction of A with osmium(VIII) oxide followed by work-up produces E which is an isomer of D. C can also be produced by addition of A to bromine water followed by heating. Ozonolysis of A produces a single product E which is a symmetrical diketone. Draw structures for A,B,C,D,and E. This is what I have so far. I am confused because I do not have a mechanism involving heating bromine water. and when I do the ozonolysis of A I do not get the same compound as the E I got from the Os reaction. Any help would be greatly appreciated

Thank you very much. I think it was just an error on the professor's part, judging by his dismissive response.

Ok, so if it is a di-bromination then br will be added to both sides of the alkene, correct? So in place of the H attatched to the C with a Cl, there would be another Br?

Sorry about the size of my writing haha. Took the picture with my camera phone. As far as where the H comes from, that is what is really confusing me. The next question actually asks to draw the mechanism of the most stable, which I believe is the first picture. However, I cannot figure out how to go from Br2 to HBr. Do you have any suggestions?

Ok, so after I posted that question I worked it out as a hydrobromation. These are the two conformations of the product I got. How do they look?

Hi there, I have a question about a question. in the picture I have attached, the question says that the alkene undergoes hydrobromination. However, to me, the reaction given looks like a halogenation, not a hydrohalogenation. I was wandering if I am correct in thinking that or if I am missing something. Thank you