ravell

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  1. The relevant formulas are clearly presented in the VETER program available at the link: ! Moderator Note Link deleted, again. If you have something to say regarding the program and its implications, do that here in writing. This program is safe, available on the Internet since 2013 and has many users, and has been cited many times in this forum. Moving this program from the Relativity section to the Speculations and removing its link without any substantive objections is incomprehensible and reflects the strange intentions of the moderator. Could you provide the recommended link to these scientific evidence and experiments confirming special and general relativity?
  2. In the program VETER v. 3.0 for verification the theory of relativity, available on the link: LINK DELETED are presented calculations regarding the observation of ticks rate of light clocks in motion. The calculations shown (numerically and graphically) in the "Frequency" and "Time" sheets, clearly prove that is not true the claim of relativity theory, that every two clocks maintaining a constant velocity with respect to each other, will both see (measure) the other as running slow. (To open this program you do not need to log in to Dropbox, but select: Download> Download directly and after opening the program in Excel, select Enable editing.)
  3. ravell

    Galaxy rotation curve

    Quotes from the link provided by Strange: „The Milky Way is a barred spiral galaxy with a diameter between 150,000 and 200,000 light-years (ly). Estimates of the mass of the Milky Way vary, depending upon the method and data used. At the low end of the estimate range, the mass of the Milky Way is 5.8×1011 solar masses According to a study published in 2014, the mass of the entire Milky Way is estimated to be 8.5×1011 M☉, which is about half the mass of the Andromeda Galaxy Mathematical models of the Milky Way suggest that the mass of dark matter is 1–1.5×1012 M☉. Recent studies indicate a range in mass, as large as 4.5×1012 M☉] and as small as 8×1011 M☉.” As you can see, there is no unambiguous data regarding the mass of Milky Way and its diameter. As it results from the above, the assumed for calculations in the program the diameter of the galaxy 200 kly and the mass around 2.5E+11 Ms, is generally correct and gives correct calculations of the speed, consistent with the observations. This excludes unambiguously, the occurrence in the galaxy of a mysterious dark matter (non-baryonic) with a very large mass of 4.5E+12 Ms, that is (4.5E+12) / (2.5E+11) = 18 times greater than its normal (baryonic) mass !.
  4. ravell

    Galaxy rotation curve

    According to data from astronomical tables from 2002, the mass of the Milky Way is 5E+41 kg that is 2,5E+11 solar masses (Ms), and the diameter of the galaxy disk is 120 kly. If we put this data into the Sagitarius BR program, with the previously given distribution of mass, but with the diameter of the galaxy enlarged to 200 kły, then we get the calculated rotation speed of the stars exactly the same as we observe (ie about 220 km/s). The change in the diameter or mass of the galaxy does not change the shape of the speed curve, but only raises or lowers the level of velocity obtained. For example, after adding that controversial dark matter, 10 times larger than normal mass (!?), the mass of the galaxy should then be about 2,5E+12 Ms, and the obtained star speed will then be about 700 km/s! For a full understanding of these relationships, I suggest you practice it yourself in the program Sagitarius BR.
  5. ravell

    Galaxy rotation curve

    This is what the uniqueness of the Sagitarius BR program is all about. You can, by trial method, model such mass distribution in the disk of the considered galaxy, which in turn results in a rotation curve of stars in the galaxy, consistent with the observations. On this basis, the program allows to analytically verify the real mass value of the analyzed galaxy and its distribution in the disk.
  6. ravell

    Galaxy rotation curve

    As can be seen from the description of the Sagitarius BR program, the mass Me of the equivalent star in the individual rings of the galaxy is calculated as follows: The modeled % mass for a given ring is divided equally into 72 sectors, and then the mass of the sector is divided equally into 10 layers of this sector. So there are 720 Me stars in each ring. Thus, if we model the total mass in a given ring by, for example, 5% of the mass of the galaxy, then the mass of each equivalent star in this ring will be Me = (5/72)/10 = 0.006944% of the mass of the galaxy. If, for example, for Milky Way, we assume a distribution of the galaxy mass on individual rings 1-20 in % as follows: 13, 1, 5, 6, 11, 1, 8, 6, 5, 5,5, 5,3, 4,9, 4,8, 4,6 4,5 4, 3,5, 3, 2,4 1,5 We get a graph of velocities of stars, which is generally consistent with the observations: The observed velocities of the stars for the Milky Way : Therefore, the calculation method adopted in the Sagitarius BR program can be considered as fully correct, which is confirmed by the observations.
  7. ravell

    Galaxy rotation curve

    The method used to calculate the velocity of stars in the disks of spiral galaxies is clearly presented in the description of the Sagitarius BR program. The link to the description of this program is given in the final part of the program. The link is as follows: https://www.dropbox.com/s/d2ywkaabxo0jd6m/SagitariusBRprogramDescription.pdf?dl=0 Below a fragment of this description concerning the applied calculation method: “ The idea of the computation program Sagitarius BR is to split an analyzed galaxy disc into twenty concentric rings of the same width. The thickness of each ring is formed of 10 layers. The thickness of the layers in the rings are adopted accordingly to assumed profile of the galaxy. Each layer is divided into 72 sectors (five degrees of arc) and the total mass of stars and gas contained in the each sector is presented as a single star of equivalent mass (Me). Thus, the model used for calculations is equivalent in size and mass with the analyzed galaxy, and it consists of 14400 Me stars, rotating in a galaxy disc on 200 orbits, with 72 Me stars on each of the orbit. The program allows: - to calculate and present a chart of the orbital velocity of stars in galaxies of any galaxy mass, calculated in multiples of the Sun (Ms), and with any disc diameter, ……….. The program first calculates the force of gravitational attraction of the Ms star, located on orbits in the consecutive rings, by each of 14 400 Me stars (F (kn) = (G Me(kn) Ms) / L(kn)^2, where k is the ring number, n the sector number, L the distance between the Ms star and the Me star of a particular sector), and then calculates for the Ms star at a given orbit, the total resultant force of attraction F by all the 14 400 Me stars of galaxy On the basis of the calculated resultant forces F of gravitational attraction for each orbit, the program calculates the rotation velocity of the stars on these orbits, resulting from the formula for centrifugal force to balance the gravitational attraction for a given orbit (F = ( Ms V^2)/ r), where r is the radius of the orbit. In total, the Sagitarius BR program version 4.0 performs over 200 000 calculations. ……………. ” The link to the program is correct, but for some inexplicable reasons has been blocked here. I therefore give it again: https://www.dropbox.com/s/a1cu74xj4ep9iyq/SagitariusBRprogramForCalculationsOfSpeedOfStars.xlsx?dl=0
  8. ravell

    Galaxy rotation curve

    The program Sagitarius BR is for many years available on the Internet and also on this forum has already been cited several times. The program is save and has many users. The program Sagitarius BR (made in Excel) is very useful, because in an interesting, interactive way presents selected calculations in the field of astronomy. The program does not contain speculations only legible, easy to verify the real calculations.
  9. ravell

    Galaxy rotation curve

    In Wikipedia: https://en.wikipedia.org/wiki/Galaxy_rotation_curve the flat curves of the observed velocities of stars in the discs of spiral galaxies are presented, which according to physicists, differ significantly from calculated velocities of stars, resulting from the luminous mass of a given galaxy. Such a significant discrepancy between the observed and calculated velocity of stars in spiral galaxies is currently explained in scientific publications, by the alleged presence of an unvisible halo of some mysterious dark matter. For example, in the textbook James B. Hartle "Gravity. An Introduction to Einstein's General Relativity " states that such an equal velocities of stars, for example in the disk of the Andromeda galaxy, indicates that the galaxy has an unvisible halo of dark matter in an amount 10 times (!) of the luminous mass. As it turns out, such explanation of the equal velocities of stars in spiral galaxies as a result of the interaction of undetectable dark matter is wrong. The concept of dark matter arose as a result of adopting the wrong method of calculating the distribution of gravity in the disk of spiral galaxies (as for a sphere!). Correct calculations of the distribution of gravity for the galaxy disk clearly show, that flat curves of the velocities of stars in the discs of spiral galaxies, result only from Newton's laws of motion and gravity for the natural distribution of luminous mass in the disk, and any mysterious dark matter (non-baryonic) is not present there. Detailed calculations proving it are available on the link: https://www.dropbox.com/s/a1cu74xj4ep9iyq/SagitariusBRprogramForCalculationsOfSpeedOfStars.xlsx?dl=0 (To download the Excel file from Dropbox, you do not need to be logged in. You only have to choose the options: download> download directly> enable editing).
  10. ravell

    Special Relativity - simple questions?

    Thank you for your post with the beautiful animation. In the opening post, I pointed out that my questions concern light clocks in motion. Two questions: 1. What in the theory of relativity means the ticking of the clock at a normal rate, and based on what data, the person on the spacecraft in motion finds that his light clock is ticking at a normal rate? 2. As we have stated already, in our example the observer on the spacecraft will receive the frequency 500 Hz of the clock on Earth when is receding, and 2000 Hz when is approaching. Thus on the basis of what data or in what way, the person on the spacecraft will determine or experience the illusion, that the clock on Earth, from which he took off, ticks slower than the light clock on board, regardless of the spacecraft approaching or receding from the Earth? This is unfortunately not true. The light clocks in motion tick slower and it is a real phenomenon. This is not a relativistic illusion experienced by an observer on Earth. This is the immanent technical feature of these clocks. Doppler measurements according to Newtonian physics will thus show for observers on both sides the same frequency of the clocks but related to the local second, which on the spacecraft is longer than on Earth. I have already answered this question in my post dated July 15: 1. What date shown on the clock display on Earth, will be seen and photographed by the observer on the spacecraft the day before reaching Earth? Traveling at a speed of v = 180 000 km /s back and forth to an object 1,5 light years away, will take 5 years according to the clocks on Earth. Thus, the day before the spacecraft returns, the clock on Earth will show on its screen the date 31.12.2024. And this date will be seen and photographed by the observer on the spacecraft.
  11. ravell

    Length contraction and pressure

    Gravitational time dilation between two levels of different gravitation, is a phenomenon resulting from classical physics (Newtonian physics) and is always equal to the delay that would have a light clock, moving at the speed that the clock would gain during a free fall from a level with lower gravitation to level with greater gravitation. This is clearly presented in the previously given VETER program available on the link: https://www.dropbox.com/s/9ljwu5wwsi0v9up/VerificationTheoryRelativity.xlsx?dl=0 This program is available on the internet for several years and has many users. Currently, there is version 2.0+++.
  12. ravell

    Special Relativity - simple questions?

    Then you will be able to post the derivation - it's time to put up or shut up. Well, I will try to show it as simple as possible. Here is a dense forest, forest, forest, forest, forest, forest, forest, forest . . . . . . L . . . L . . . . D . . . . . . . ---- Here is our train >> ------------- v --------------- train >> --------------------- A ------------------ S = v*T----------------------B D - Distance between the forest line and the railway line v – Speed of the train u - Speed of the sound pulse in open air. T - The tick time that elapses from the moment of sending sound pulse from the train (point A) to the moment of returning its echo (point B). The tick time of the sound pulse for train at rest (v=0) is To = 2D /u. The tick time of the sound pulse in open air for the train in motion at the speed v is T = 2L /u, where 2L is the path length of the sound pulse, and L is: L = ( D^2 +(S/2)^2)^0,5 = (D^2+(v*T/2)^2)^0,5 Thus, the tick time of the sound pulse in open air for the train in motion will be: T = 2L /u = 2(D^2+(v*T/2)^2)^0,5 /u Solving this equation with respect to T, we get: T = 2D/(u^2-v^2)^0,5 = (2D/u)/ (1-v^2/u^2)^0,5 2D/u = To then T = To/(1-v^2/u^2)^0,5 The above formula expressed in the form of the frequency F = 1 /T will take the form: F = Fo*(1-v^2/u^2)^0,5 If we now replace the word FOREST with the word MIRROR and the speed of sound u with the speed of light c, then our example with the sound changes into the light clock with the same formula as for sound: F = Fo*(1-v^2/c^2)^0,5 Thus, the classical (Newtonian) physics clearly shows that in case of a spacecraft or train in motion, the formula for the tick time of the light clock in a spacecraft is exatly the same as for the train and sound in the open air, and as shown above, this has nothing to do with relativity.
  13. ravell

    Special Relativity - simple questions?

    You're right. I know that Janus has already given this in his first post. But as I showed on the basis of classical physics, that in our example, we get axactly the same values as in Janus’ post, ie. the values of F = 2000 Hz for approaching and F = 500 Hz for receding, then Strange commented it as follows: "Except that your results are wrong, because you have not taken relativity into account." And no one commented on his statement. The formulas given by me concern the Doppler effect and the delay of the light clock in motion, which results exclusively from classical physics. I was hoping that my post from Saturday would make it clear. If, however, this is still a bit incomprehensible, then I am not able to present this case more simply. Classical physics and theory of relativity are separate matters even on this Science Forum. If, for example, you measure the frequency F = 1000 Hz generated by the clock A (at rest) with a meter clocked by another clock B, which for whatever reason (wrongly tuned, sensitive to motion, temperature or shock, etc.) is at a given moment 10% slower than clock A (about which you do not know), you read on your clock meter B that the clock A is in a hurry, because in one second of your clock B, you receive 1.1 x 1000 Hz = 1100Hz from the clock A. During the movement of clocks, the Doppler effect must be additionally taken into account. I can not explain it more clearly.
  14. ravell

    Special Relativity - simple questions?

    Why no one answered clearly to the simple question previously asked to Strange: If my calculations are incorrect then please show what specific frequency values F will see, according to relativity, an observer on Earth and on a spacecraft for a given speed v = 180 000 km /s, when approaching, and when the spacecraft is moving away, if Fo =1000Hz? If the speed v = 180 000 km /s seems to someone to be deliberately chosen by me, then please provide these values F for any other speed v you choose. The formula given by Studiot as the correct one according to the theory of relativity, is exactly the same (!) which I presented in classical physics: F = F1 * c /(c + v) where F1 = Fo * (1- (v /c))^2)^0.5, and it is only in a slightly modified mathematical form. Please check it out.
  15. ravell

    Special Relativity - simple questions?

    If the above numbers are wrong, would you be so kind to give here the right value of the frequency of the clock on Earth that the observer on the spacecraft would see: a) when moving away ???? Hz b) when approaching ???? Hz And the same but for the observer on Earth ?