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haggy

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Everything posted by haggy

  1. Doron, it is evident that there are two options here: 1) You are severely pedagogically challenged 2) You are incorrect So which of the two is it? As for your simple questions: What a load of garbled rubbish!
  2. In fairy land, much like those "proofs" that you think are correct.
  3. Blah => Blah => You're talking (or typing) tripe just like I am now
  4. Blah, blah blah. By the above argument, Doron, you are wrong. Can't you see that "Blah, blah blah." is a perfectly valid mathematical argument in your world?
  5. Doron, we love your MyWay_XOR_TheHighway attitude
  6. You obviously don't know much about Fermat's Last Theorem.
  7. haggy

    x not= x

    Gee, I think we all find that surprising You ramble on about how Mathematics has to conform to your changing apples and how x != x. If you denote "The exact state that an apple is in" by x (if that were quantifiable in some manner), this does not imply that x != x. Your changing apple (no matter what the time) does not mean this in the slightest. What it would rather mean is that your apple is in a new state x' and not its original state. The best you could say is that x != x'.
  8. haggy

    x not= x

    Someone whose reponses are quite similar to yours. A typical conversation with Doron (*must spell correctly so it's not deleted*) goes something like this:
  9. haggy

    Transfinites?

    *bangs head against wall*
  10. haggy

    Transfinites?

    Why are you so averse to having what you call technical definitions. The whole point of definitions is to ensure absolute clarity concerning the issue at hand. If one doesn't maintain absolute clarity there is room for confusion. An example of this would be the following: Say we were to try to prove some theorem about triangles and it started... Let P be the centre of the triangle. Now, to the person initially writing it this might seem absolutely clear in meaning. But does this person mean the incentre or the circumcentre etc? Doron, dealing with the concepts of Infinity, Number and Limit in a formal manner isn't a cop-out. Rather it is a means for all involved to know exactly what is being considered at a certain point. This is where much of your explanations don't have any formal definitions that would ensure absolute clarity.
  11. Maybe you could consider looking at some Coding Theory. Any electronic communication is reliant on Codes, so it is a field that has direct applications.
  12. What is the scope of the essay? Are you expected to give some sort of an overview of a particular field and its applications?
  13. It's just the basic rules of modular arithmetic. Google "modular arithmetic". Remember' date=' I'm using the "=" sign instead of the congruence sign. It's just quicker to type =. I didn't say that. I said: 8^2 = 64 = 1 mod 9 Therefore, (8^2)^2160 = (1)^2160 mod 9
  14. Wow, Doron, your arms are so big. I envy you.
  15. Do your arms get tired from all the hand-waving?
  16. 1 Inch = 2.54cm 193cm = 76 inches Thus he's 6'4", same here.
  17. Let S(x) = Sum of the digits of x Thm: S(x) = x mod 9 (more generally Sb(x) = x mod (b-1) if we are working in base b) S(8765^4321) = 8765^4321 mod 9 = 8^4321 mod 9 8^2 = 64 = 1 mod 9 Therefore S(8765^4321) = (8^1)*(8^2)^2160 mod 9 = 8 * (1^2160) mod 9 = 8 mod 9 Thought this might help a bit.
  18. C = 8. Merely calculated using Mathematica. Haven't had a chance to check for more general cases yet.
  19. 2004 = 167*3*4 These are relatively prime to one another. 2196^n – 25^n – 180^n + 13^n = (13*167+25)^n -25^n -(167+13)^n +13^n Therefore 2196^n – 25^n – 180^n + 13^n = 25^n -25^n -13^n +13^n (mod 167) 2196^n – 25^n – 180^n + 13^n = 0 (mod 167) Likewise 2196^n – 25^n – 180^n + 13^n = 0 (mod 3) 2196^n – 25^n – 180^n + 13^n = 0 (mod 4) Therefore 2196^n – 25^n – 180^n + 13^n = 0 (mod 2004)
  20. Not impossible, just a whole lot harder. As an aside: If your certificate for your https site isn't verified by someone like Verisign, you'll be susceptible to a meet in the middle attack. Concerning careers: I'm doing Maths, not in it for the money, more for the enjoyment of my career.
  21. I haven't looked at this closely but you need to consider repetition of vertices. A path is a walk that has no vertices repeated. I think your working will change to something like n "choose" j/2 etc.
  22. A bit of knowledge of Algebra(finite fields) is useful when considering AES/Rijndael. For that matter "A bit of knowledge of Algebra" is useful, period.
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