  # concept07

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http://www.photoleech.com

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renewable energy
1. i made a really fast (2 minute) php script so that you can review my work to determine if i am on the right track or if i am way off in my numbers <?php $cfm = 1900;$length = 30; $width = 10;$height = 10; $minute_seconds = 60;$hour = 60; $mile = 5280;$squarefoot = $length *$width * $height; echo "<br> total cfm =$cfm <br>"; echo " <br> square foot $squarefoot<br>";$minute_air_speed = $squarefoot /$cfm; // per minute air speed echo " <br> minute aire speed: $minute_air_speed <br>";$feet_per_second = $minute_seconds /$minute_air_speed; $mph = ($mile / ($minute_air_speed *$hour)); echo " <br> feet per second: $feet_per_second <br>"; echo " <br> MPH=$mph "; ?> the above script will produce this following output total cfm = 1900 square foot 3000 minute aire speed: 1.5789473684211 feet per second: 38 MPH= 55.733333333333
2. Ok this is a bit of a strange question but this is my last place to turn. Ok High output fans or any fan really is measured by CFM (Cubic feet ,Minute) Ok now what i am interested in is how to convert a fans CFM to actual WINDSPEED MPH I am sure some variables would include the following. Size of Area, Resistance, CFM, and possibly other things. But is there a way to calculate this or is that something that is just impossible. and i would just have to build a wind tunnel and run a fan with X CFM coming out of it in a specific area and then measure windspeed. i would hope not, i would like to think that is a way to mathmatically figure it out thanks for anyone here who can help with this, And what the basis of this question is for is wind tunnel testing. THanks for your time and reading this post and hopefully and informative answer. X