Anilkumar

Hi Spyman, Nice piece of explanation there, But, this part I didn't understand. Can a battery give a higher outflow than what the battery is able to support? Does the word 'then' stand for 'it means/shows that' here and 'empties' stand for 'has emptied it' Thanks.

Well, Thats it. Bulls-eye. Thanks a lot. You have not corrected me. It shows I have understood the theory correctly. There are other doubts. But different matters. May be I should take-up a new thread. Well, thanks again fellows, for helping out. Regards.

Hello, Great! Thanks man. For the painstaking explanation. As I had said earlier, I was chewing it the whole day. In the afternoon I did, like you said. Pondered over the water analogy of Ewmon; 'the waters of a river's branches splitting or combining' broke the ice. And now your detailed explanation confirmed it. If I have understood it rightly [i am doing a recheck, while you guys are arround, to correct me if I am wrong.] here in both these analogies the equivalent of EMF in electricity is GRAVITY, right? I went through the books again. Got a clearer understanding now, of the thing called ELECTRIC POTENTIAL similar to GRAVITATIONAL POTENTIAL; both of which are PE per charge and mass respectively and are independent of charge and mass respectively [Here charge and mass in the fields of electricity and gravity respectively are analogical, if I am right again.] Voltage is Electric potential which is Joules per Coulomb. So till the last charged particle with PE exists in the battery, it gives the rated voltage reading. And when that too becomes 'neutralised' [tell me if this is the right word] the battery will not give any reading, I suppose. In the gravitational analogy, two objects placed at equal altitude have the same GP similar to two PD's accross two resistances connected in parallel, right? But when they are connected in series, it is like placing the two objects, one at greater altitude than the other, right? One more question has proped up in my mind. [Can I go on spilling my doubts here? Hope so.] How do they make one battery more potent than the other? A stone or water can be lifted to higher altitudes to give them necessary PE. But how is this achieved in case of charged particles? By using one chemical more potent than the other to displace them, or what? Thanks, Regards.

Thanks everybody for your kind attention. The allegory of chains & choke points given by Spyman is a little bit convincing. But I am still chewing it again and again to make it digestible. [Pardon me fellows, I am slow at digesting]. But [quite many 'but's here] what is the meaning of 'when they are in parallel they all eat from the top'. The fact that the voltage when measured accross the terminal junctions of the parallel branches is equal to the rated voltage; is agreeable. But why is it, the same at the terminal ends of the individual resistors connected in parallel? Why does it not split like everything else [the electric current, water flowing through a branched pipe] does? The little observation by TonyMcC is well known. I know it is so. But why? Is there an explanation? And what I meant to say regarding the battery problem was; we know that voltage is joules/coulomb [energy spent per unit charge to displace it and it is proportional to the number of charged particles displaced.] Then when the battery goes on discharging; the number of charged particles reduces. But then why does the voltage accross its terminals, still show the rated voltage? Why is it not reduced? I think Ewmon's comparison 'of the waters of a river's branches splitting or combining' is finally getting me somewhere. Thanks everybody for your time. It would be great if you would carry this thing on, till that thing gets into my head. Regards.

Hi Spyman, Thanks for the answer. But I don't understand how voltage is location dependent? Primarily voltage forces the electrons to move. It is natural that resistors in series eat-up the voltage, and eventually it drops. But the same should happen with resistors connected in parellel. As, they too eat-up voltage. Resistors absorb energy. So they have to absorb energy, irrespective of how they are connected. Then why does the voltage not drop at each branch of the parallel connection? Thanks again for caring to answer. Regards.

Why is the voltage accross the branches of parallel circuit, the same for all branches? Why dose a dead battery show its rated voltage accross its terminals? Thanks fellows, if you could kindly help me understand these things.