# --00--

Members

11

• Quark

10

1. ## Integral of tan

Please could you tell me how to integrate tan^3[x] without integration by parts. i know that tan^2x = sec^2 x - 1 thanks in advance.
2. ## Logarithms

thanks. ive worked it out now...
3. ## Logarithms

This is probably really easy for all you guys, but I can't see the answer: Given that log 2 = 0.3, show that log 5 = 0.7 Thanks in advance.
4. ## 1?

^assuming that is correct^ 31131122211311123113321112131221123113112211121312211213211321322112311311222113311213212322211211131221221113222123211211131211121311121321123113112221231221322113112211

6. ## Square root of 0.9

the thing is, this was set as a sort of 'brainteaser' question, so i was wondering if there was a simple, almost 'sneaky' way of doing it...
7. ## 1?

11131221131211131231121113112221121321132132211331222113112211 - i think...!
8. ## Square root of 0.9

Does anybody have any ideas on how to work out [imath]\sqrt{0.9}[/imath] without a calculator (to approx 10 d.p.)? I know there are a few methods for working out for working out square roots by hand, but i was wondering if there was a cleverer/easier way of doing it.
9. ## Hehe this is funny!

- that's true. I originally saw this proof for 'teletubbies', for which it worked, because they were the PRODUCT of time and money (hence multiplication)...
10. ## Derive pie

actually' date=' [math']\pi=\frac{circumference}{diameter}[/math]
11. ## 0 x infinity = -1 ?

i was wondering if somebody had any ideas about this: the gradient of a horizontal line = 0 the gradient of a vertical line = infinity but the product of the gradients of perpendicular lines is -1 so does that mean that 0 x infinity = -1 ??? ... or is there something in the proof for the product of the gradients equalling -1 which excludes it for these values?
×

• #### Activity

×
• Create New...