JoeMK

i'll give it to u at school

co-sign!! LOL

anyone has an idea about the Mass vs distance in circular motion graph?

i really don't know how to connect red shifts and cosmicbackradiation with any predictions of a static universe

Thanks buddy It makes better sense now

It seems illogical that a heavier object needs the same velocity to travel in orbit as a lighter object. I know that gravity acts on all bodies equally, but i'm really having troubles imagining it. using the formula: m2*(v^2)/r =G*m1*m2 / (r^2) assuming m2 is the mass of the satellite, it cancels out... are u sure that means that the mass of the body doesn't affect it's velocity

Are u sure, cuz i don't believe that's right

We gotta do sum calculations, but i don't think they gotta be that complex. Just a good theory behind a logical explanation

I know that the stars release large amounts of heat as they burn, but the temperature of the universe does not increase, as it is constantly expanding. If the universe was static, then it'll obviously be much hotter, and most probably we wouldn't be alive. I need help with the prediction, and as well as to connecting it with the idea of "Red Shifts" and "Cosmic Background Radiation" Thanks

Imagine that the universe is static and not expanding. Predict the observations that would be made in regards to: a. Red shifts in glaxy spectra b. The temperture of cosmic backgorund radiation

I have attempted to research this, with no luck i need ideas to get me started

The absorption and re-radiation from solid and liquid objects We have to design our own comparison experiment, to find out how different substances absorb or reradiate heat(or light). We do not have to do the experiement. Suggested equipement: A heat or light source, a bar heater or an overhead projector, a heat detector, your choice of solids and liquids. Any ideas, just need ideas

Mass vs distance is kinda impossibble, cuz u cannot show any time or distance progression. so i agree on the graph I'm a bit unsure about the force vs acceleration graph however.