Kerrowman

Can anyone help me calculate the Gibbs free reaction energy in a Lithium Iron Phosphate battery with the combined equation? LiC6 + FePO4 → C6 + LiFePO4 Since the Lithium ions are acting as intermediaries and are on both sides, I understand that they can be removed from the equation. Since the formation energies of all these molecules are not listed in any tables I can find, I presume I have to work from the components of each molecule, so using the Gibbs formation energies of Li+, C6, Fe+, Fe2+ and PO43-, before I can use the combined equation above? For example to get the ΔG°f (FePO4) do I use the equation: Fe3+ + PO43- → FePO4 and then just add the ΔGof Reactants together, which would be -5 + (-1019) kJ/mol I have found the following formation energies so far: ΔG°(Li+) = -58kJ/mol, ΔG°(C) = 0kJ/mol (standard state?), ΔG°(Fe2+) = -79kJ/mol, ΔG°(Fe3+) = -5kJ/mol and ΔG°(PO43-) = -1019kJ/mol For the combined equation I then need to use ΔG°r = 𝛴 ΔGof Products - 𝛴 ΔGof Reactants, however I am not clear how to get the formation energies of all the components in the first place. Thanks