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Jakerm1995

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  1. I am currently confused as to which stats test to use. I am checking for the number of species orders found between managed and unmanaged dune slacks. I have already done a Simpson's index for diversity, but I assumed that for this assignment I would also need to do a significance test. I did an ANOVA and Tukey test, and no significant difference found in either. I am wondering if I am supposed to see no significant difference, and just leave it at that or whether or not doing it wrong and that I am supposed to do a different type of test. I hope this makes sense. I have attached screenshots of both the tests and my data. Any suggestions welcome, thanks for reading
  2. Hey, apologies yet again for the delay. I've had a friend moving in and also one staying with me. Little time to focus on my studies, which isn't good really considering my deadlines. This piece is due in tonight, so I am really going to focus now and get it done. That explanation fits yes, so I appreciate your help a lot. I may need some additional help on the maths side of things, if I ever meet you, I owe you beers for all the help!
  3. Sorry again, busy days atm :'D Thanks again for all the help! The water will enter the worms cells through the skin and, thus, the worm will get bigger? Sorry if that sounds stupid ahah
  4. Hey, sorry for the delay. So to answer your question, I assume that it's just that water will pass through to the more concentrated solution from the weaker one?
  5. It's just the salinity. I have posted a picture of the different seawater treatment concentrations, so you can sort of understand what I mean :'D I hope this helps. Thanks again for your help! As for your earthworm comment, what do you mean by burst earthworms? Sorry for all my stupid questions 😅
  6. 125% Seawater* Sorry typo I can't seem to edit it. Btw I am still yet to complete those calculations so I apologise for not following up your replies.
  7. To provide some context for this question: I have 4 seawater treatments at different salinities. At 50% seawater there was a 51% increase in weight over a one hour period. At 75% seawater there was a 26.9% increase in weight over 1hr. 100% seawater = 6.18% increase over 1hr. Finally at 125% water, there was a 7.25% decrease in weight over 1hr. I understand this has to do with osmolarity. The species in question are euryhaline osmoconformers, I have a very vague idea, but would very much appreciate some assistance in understanding what is happening here 😅 Any help is welcomed and appreciated! Thanks for taking the time to read this post.
  8. Apologies it seems that the moderators banned my other account because I had more than one account. I just totally forgot about this one :'D But I can respond via this account now. Thanks again for your help on this and the other post, I'll update you as I go
  9. I have two line equations representing two temperatures: Temperature 25C: y= 0.7479x + 0.6586 Temperature 33C: y= 1.050x + 1.601 I am tasked with using these to work out the difference in development rates of a particular species under each temperature. Y= development time and x=Time. I am confused with how to use these two equations to calculate the difference in growth rate. As when I apply a percentage increase calculation to temperature 33, I calculate an 87% increase over 10 hours, and with the 25C i see a 92% increase over 10 hours. It should be that the 33C has a higher development rate and so my calculations must be wrong 😕 I am very confused. Any suggestions are much appreciated (bare in mind, I am a noob at maths). I have attached an image of the graph i've made using Rstudio, as well as the question being asked. "You should use your two line equations to work out the difference in development (in standard developmental hours) at a certain time (actual hours) between the two temperatures. If you do this for 24h (actual time = x value), then you already have a value of developmental hours/day. From then you just need to factor in the temperature difference as well to get a final value in h/°C/day." Thanks a lot!
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