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zyu2ranger

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Lepton

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  1. For M: Carbon 1 has the aldehyde; carbon 2 has the methyl group. Carbon 1 priorities: 1) C-Br 2) C-C/Br/CH3 3) C-CHO - I get an S; carbon 2 priorities: 1) C-Br 2) C-C/Br/CHO 3) C-CH3 - I get an S (it looks R but the H is in front so reverse to S). For N: same priorities as M. Carbon 1 is R; and carbon 2 is R. For O: same priorities as M. Carbon 1 is R; and carbon 2 is S. For P: same priorities as M. Carbon 1 is R; and carbon 2 is R. I think where you're making the mistake is that you're making the aldehyde the second priority and the C-C-Br group third priority; however, the C-C-Br group is second priority. Think of playing the card game war. I have an A, you have an A. Go to the next card. I have a Q, you have a K. I win. Does this help?
  2. Hello. I am struggling with a problem. I have attached it. I cannot rationalize a reasonable mechanism for the transformation of the reactant to the production shown. The initial problem is given at the top of the image. Thank you for any assistance. I have tried to protonate the -OH group and then have an enol kick out the water to form a carbocation; I've tried to make the enol at the top of the right ring make a 1,3-dicarbonyl and close the ring on the carbon adjacent to the initial OH group... none of these are working. Please assist! Thank you in advance.
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