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RaytjeKn

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About RaytjeKn

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    Physics
  1. But I want to bring back my initial idea. I thought of using black paint which I put on the sides of the ring. Because of the really high emissivity of a black surface it is ideal to measure the temperature of the paint using a IR thermometer which I already have. Only concern I have using this technique would be, that the paint's temperature might be a lot lower because of the bad heat conductivity of non metals. Although if I put a very thin layer on, I don't think it would really be a problem. Also I found this product: https://www.conrad.nl/p/voltcraft-tp-205-oppervlaktesensor-100-tot-300-
  2. O it definitely shouldn't this question is a part so small of the whole part. My work is to make a report about a certain subject. Which in my case is Generating electricity with the Leidenfrost effect. We are not oblidged to conduct an experiment, but we are. We are also allowed to get any help we get, this is also research. Me discussing and asking questions in this manner is also a way of research. My teacher totally allows this. I don't exactly know what this report was, but this is my opinion.
  3. I guess I would need highly heat conductive glue. So you are suggesting to glue the RTD with a really thin layer of glue tot the ring. Which part of the RTD should I glue to? The plexiglass side or the platinum? Yes it doesn't have to be accurate tot the 3rd decimal, but I would like it to be around ±3°C. What is your intention with the glass wool exactly?
  4. I have a multimeter which I seems like it could measure the resistance. The RTD i mentioned earlier from TE, has a data sheet which provides a graph. It shows the connection between the temperature and the resistance. My multimeter should quite easily be able to measure such high resistances. So I think I don't need the circuits you delivered me. I think it should be as easy as connecting the wires of my multimeter to the probes of the RTD without any other circuitry, read the readings of the multimeter (Ohms) and see what the according temperature would be. But would like I asked earlier it j
  5. I will be eating right now. I will be back with an answer in about an hour or so. Okay I took a look at the wikipedia page. I read about the different types of RTD's from which i concluded that a thin film RTD would probably work best. Like you said in the comment below "Can you not cement a small RTD (resistance temperature detector) to the ring and set up a suitable measuring bridge ?". You probably mean that I should remove the epoxy glass that is present on most thin film RTD's and solder the whole maze of wire tot the ring. Is the image below what you mean? You
  6. Well Like you can see on the third image the ring is split up in two parts. But I think I would quite easily be able to drill a hole all the way through the ring if needed (which means like 40mm deep). When the thermometer sticks out to the side whe could support it with something like a wooden block for example. I do have a supervisor, but he doesn't know much about the practical side of this stuff since he just studied physics, but even if he would know, he is not able to provide us with enough time to get this done. Indeed a smaller sensor to me would seem better. But all those RTD, N
  7. Whoops my fault. It's supposed to be 40mm (4cm).
  8. Okey this is exactly what I was looking for. I really see where you trying to get this. But just to make everything a lot more clear I have some pictures. You say a hole of 75mm deep. I think you mean 7.5mm deep because the ring is only 4cm wide and like 1.5cm high. The images don't include the object supporting the thermometer on the right side. I'm not 100% sure this will work as you can see in the 3rd image, the ring is split into two pieces. I can't use the top of the ring because there will be an aluminum thin circle plate on top of the whole ring (with the same 4cm diameter). I guess I c
  9. Okay I'l start from beginning to finish. I am with a friend of mine conducting an experiment with the Leidenfrost effect for our graduate year. Our goal is to create a system which is able to generate electrical energy using the Leidenfrost effect. Our setup looks like following: We have an electrical plate which heats up the ring, the plate is not capable of using a certain temperature. On the plate we put the Leidenfrost ring, with water in it of course, on top of that a little alluminium circle with holds 4 magnets which generates energy using the Lorentzforce. But when conducting this the
  10. Would putting the thermistor circle on the surface give an accurate temperature? Seems like I would have to calibrate the sensors. But calibrating them would make me have to measure the temperature again.
  11. Thanks for the fast reply. The ring is 400mm in diameter. How would we doing this exactly? This RTD is new for me so I don't exactly know what to do.
  12. So we are conducting a experiment with the Leidenfrost effect. We are trying to generate energy using this phenomenom. The leidenfrost effect occures whenever the temperature of the heated surface gets to around 210 degrees celsius. Reaching this exact temperature is important for the experiment. We thought about using a IR thermometer. But soon found out that because of the emissivity of Aluminium it wouldn't work. So we started to think about other ways to measure the temperature. We still haven't found a solution to this, but have come up to an idea. We thought painting the Aluminium Leiden
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