Hi,
I’m not sure if I’m posting in the right forum but please let me know if I’m not.
I’m practicing for the test and trying to prove that two boolean algebra expressions are equivalent:
x1=a′b′c+bc′+ac+ab′cx1=a′b′c+bc′+ac+ab′c
x2=b′c+bc′+abx2=b′c+bc′+ab
I got up to here:
LHS
a′b′c+bc′+ac+ab′ca′b′c+bc′+ac+ab′c
RHS
=(a+a′)c+bc′+ab=(a+a′)c+bc′+ab
=ab′c+a′b′c+bc′+ab=ab′c+a′b′c+bc′+ab
=a′b′c+bc′+ab′c+ab(c+c′)=a′b′c+bc′+ab′c+ab(c+c′)
=a′b′c+bc′+ab′c+abc+abc′=a′b′c+bc′+ab′c+abc+abc′
=a′b′c+bc′+ab′c+(b+b′)abc+abc′=a′b′c+bc′+ab′c+(b+b′)abc+abc′
=a′b′c+bc′+ab′c+abbc+ab′bc+abc′=a′b′c+bc′+ab′c+abbc+ab′bc+abc′
The next step is supposed to be
=a′b′c+bc′+ab′c+ac+0+ab′c
I do not see how they got to that step. If someone give a pointer to what I should be doing next for this theorem, I would be beyond grateful.
