Kimistry

I have absolutely no idea. it's the assessment question It says mol dm-3

Thanks for the help. I think it is supposed to say 150cm3. I think question b(ii) is asking how much is in the solution stated in (b)

Hello, I have got this question i'm having difficulty with... Here it is: (b) A beaker contains 250cm3 of 0.3 mol dm-3 calcium hydroxide Ca(OH)2 solution. (i) How many moles of calcium hydroxide are present in 150cm3? (ii) What mass of calcium hydroxide is present in the solution? Can someone please help me to breakdown question b(ii), Here is my answer: 250cm3 in dm3 is 250/1000 = 0.25dm3 0.25 x 0.3 = 0.0075 moles of calcium hydroxide so... 0.0075mol x 74mr = 0.555g of calcium hydroxide?