Bean_Spiller

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1. What is x?

20x=6(0.6-2)+8(4+0.8x) 20x=3.6x-12+32+6.4x 20x=6.4x+3.6x+20 20x-20=6.4x+3.6x (10(2x-2))/10=6.4x+3.6x/10 2x-2=.64x+.36x 2x-2=x +2 & -x 2x-x=2 2x-x=x Therefor, x=2
2. Which is a faster method for solving unknown variables: Matrices or Algebra

Personally synthetic division followed by the quadratic equation was uber expedient
3. Help with an E(12) GUT CounterProof of Bell Inequality

4/3pi(7e-7^3)/(4/3pi((3^19)^3))=2.1846537e-46 m^3. In other words, the 19th iteration of the photon sphere is composed of spheres with 2.1846537e-46 cubic meter volumes. But if the planck particle is truly 9^28 times denser than a photon it has the weight of a photon packed within 1/9^28th the volume of that photon, the zeroth iteration of sphere 28 will be literally the 19th iteration of the photon sphere, viz a viz the first iteration of sphere 3 would be S(2-58) of the photon sphere & would be 9^3 times smaller than the photon sphere; ergo we divide 2.1846537e-46 by 9^28/3^19=4.5028391e+17 & we get 4.851725e-64 cubic meters for each sphere comprising the zeroth iteration of sphere 28. There's (((4/3)pi(3^19)^3)/(4/3pi^3)=1.5293645e+29 spheres upon the zeroth iteration of elementary particle 28 & 1.5293645e+29 x 4.851725e-64 = 7.420056e-35 m, which is approx. 7 times the planck length (exactly how many times faster QE is than c). So sphere 29 must be a black hole particle hence why there's only 28 elementary majorana fermions making this an e(12).

5. Help with an E(12) GUT CounterProof of Bell Inequality

Because every other coordinate outside that sphere in this system is connect to it, plot by plot. So if coordinate x begins on one side of the sphere in plot one, by plot 3 that same x coordinate will be on the opposite side of that sphere. This is equivalent to that photon moving from one location relative to a stationary observer, to another location relative to that same stationary observe by one planck length per planck time. The rest of it is not gibberish but in fact crucial developments that correct formerly erroneous elements of my conjecture.

*fixed
7. Help with an E(12) GUT CounterProof of Bell Inequality

1. Vectors have no centers but spheres do 2. Assume it's a commonly use phrase in mathematics.. Okay, so 7e-7/3^60 = lp. Basically you have sphere that's 7e-7 meters, blue is normal (plot 1), red is inside out (plot 3) that travel 1 lp per tp (..c..). At first you get a red sphere that's half the size of the original (plot 2), that's the result of dragging the x,y,z lines through the center of the sphere by the length of it's radius. The change from plot 1 to plot 2 represents a graviphoton because it pulls every vector in the e(12) by the radius of that sphere. Plot 2 has no charge & is a photino. Plot 3 is a fully sized red sphere, that's the result of dragging the x,y,z lines through the center of the sphere by the length of it's diameter. This is an acceleron because it pushes every vector in the e(12) by the radius of that sphere. All of these: & https://en.wikipedia.org/wiki/Category:Hypothetical_elementary_particles Would represent some of 28 possible negative, neutral, & positive charge majorana fermions in this e(12). There's 84 possible elementary particles which represent the 28 majorana fermions stuck in one particular charge by one another when within a composite particle or when interacting in nature. There only 28 possible majorana fermions, each consecutively heavier than the previous one with a 29th planck particle (hollow black hole/reverse continuum constituent) because you can fit 8 spheres around the surface of a sphere, if these 9 spheres represent photinos that are about to become accelerons in the next tp, than they will become a neutrally charged particle with 9 times the mass in 19th of the volume of a photino. You can do this 27 more times before you exceed the planck mass I calculated that the entire 28th sphere would be a planck length. Remember you can fit 9 spheres within a sphere with 3x their volume, so at S(19-41) of sphere 28 your largest spheres are 3^19 times smaller than your original photon sphere so you have to multiply them by some 4/3pi(7e-7^3)/(4/3pi((3^19)^3)) before dividing by 3^19 times 9^28...
8. Help with an E(12) GUT CounterProof of Bell Inequality

That's not what I said. I said "dragging the vectors through THEIR centers" you ass you me'd I meant the vectors when I said "THEIR" centers when in fact I was referring to the spherical coordinates not the vector coordinates being dragged through the centers of the SPhERES to create your next plot in emulating particle charge under a uft.
9. Help with an E(12) GUT CounterProof of Bell Inequality

Yeah that was the dark matter obviously baryonic matter doesn't experience sub-planck transformations (sphere inversions) you're not inverting the spheres so much as dragging the 12 vectors through their centers to mathematically emulate a charge under uft
10. Help with an E(12) GUT CounterProof of Bell Inequality

Oops no another 25 morphisms before you'd run out of iterations b/c 42-18=25, after morphism z, representing dark matter particles. 25 + 26 is X/12^51 for your last 48 inverting spheres in all 12 planes, after that the sphere's get reduced exponentially in size & quantity with each fusion with others of their nature & after that you get merging singularities built from combining planck particles of the original pre-combined photons & represented by singular sphere inversions. Actually the 4 circles for the 84 spherical coordinates at each plane of S(0) would be found like this:
11. Help with an E(12) GUT CounterProof of Bell Inequality

Morphism A: S(2-59): Root System: (X/12,Y/12) Morphism B: S(3-58): Root System: (X/12^2,Y/12^2) Morphism C: S(4-57): Root System: (X/12^3,Y/12^3) etc etc... Morphism Z: S(17-43): Root System: (X/12^26,Y/12^26) S(43-17)=an S(0-26) w/the spheres of S(26) being 1/3^26th the size of the spheres of S(0) Actually more like Morphism D since the electron radius is 10^-12 m & the photon is like 7e-7 meters. For S(0) of that Morphism D you can get 7x7 spherical coordinates at T(t)/2 which is the uber electron neutrino, & 7x12 spherical coordinates at (T(t)/2)+(T(t(.5))) where the sphere volumes shrunk to 7/12ths their normal size. Our observable universe represents the iteration of the uber positron of Morphism D where the sphere volumes got reduced to 1/225th their original size from T(t) to T(t)/2, (7/12)/(1/225)=131.25 which is ~ 3^5ish at the spherical coordinates of S(4-5) of Morphism D. The uber quarks & gluons are the sphere volumes at S(0) You actually get your strangelets aka unobservable (without the use of a quantum entanglement based form of superluminal spectroscopy) "Dark Matter" particles at Morphisms 27-60 or Mophisms Z2-Z34, after that you have anything from fusions of planck particles to mergers of SMBH singularities which are simple particles to graph I mean they're regions of the reverse continuum's brane represented by singular sphere inversions where sub-planck dislocations in the fine structure constant of the spacetime foam lead to Hawking radiation and the most fundamental fluctuations in the Higgs Field in the deleterious di-brane.
12. Do you think this is true in science or not?

I'm liking the responses in this thread