dung pham

The objects are accidentally located at position M3 and have a G3 value. Have G3 > 0 and the object will push away. Dark energy comes from here

Galaxies are formed in different states. Galaxies have outer objects that move at small velocities. Its centrifugal force is not much. It will stand at M1 and be worth G1. If G1 = 6.67E-11, then the galaxy has no dark matter. Galaxies with external objects moving quickly. Its centrifugal force is large. It will be pushed to position M2 and have a G2 value. Depending on the value of G2, that galaxy's rating has more or less dark matter.

I suppose you are insulting him and inadvertently you offend Thomas Edison as he only finished second grade and was expelled. Evidence of G is very much. You take the time to use google and you will find http://www.blazelabs.com/f-u-massvariation.asp

https://www.sheldrake.org/about-rupert-sheldrake/blog/how-the-universal-gravitational-constant-varies It looks like you did not read my paper carefully. G increases with distance and gravity also increases. If calculated according to the old method, gravity is 1, then in the new method it can be worth 2 or 3 ....This forces it to use larger velocities (compared to older calculations) to counter gravity. The gravitational lensing is very easy to understand. If the Earth has its own atmosphere, galaxies also have its "atmosphere". If the earth's atmosphere can bend light, then ..

I do not say is to reject the old theory. I just want to raise it to a new height. If the old theory was perfect, then the problem of dark matter and dark energy was explained. There are a lot of new theories to explain this. But they are far more complex and difficult to understand than dark matter and dark energy. The motion of objects in the universe challenges every theory we have. Why do you think that the sun is running around the earth and not the earth running around the sun? Dark matter and dark energy are problems that can be explained simply by thinking differently about G. The fact is that scientists use Gravimeter to measure the gravitational acceleration of the earth. But after removing the influence of the moon and the sun, it gave a catastrophic result. What do you think about this?

Theory is simply theory ! . Has anyone used it to calculate and give a reasonable result? There are so many confusing things in Scattered disc that people can not explain.! If we go the old way, we will not be able to explain the mysteries of the universe.

Dark matter in galaxies is very different. There are galaxies where dark matter accounts for 99/100, but there are also galaxies with no dark matter. Calculating it is a very complex matter. It requires a lot of data, effort and a powerful computer. All of these I do not have. My article is just in the process of being formed. It needs the help of the scientific community to do science! Nasa has sophistry sometimes very humorous. Hubble is an example of this humor. Their plan is still in the process of controversy. Another problem is that the kepler3 has been proved very well by theory, but the reality is ......... ????

Electric fields, magnetic fields ... exist in two opposing states: · charge (+) and charge (-) · north pole and south pole Gravitational field has something wrong because it only has gravity without repulsive forces. Let us now assume that the "gravitational constant G" is not invariant by distance. It can take negative values, positive and zero. · When ( G < 0 ), it will have gravity · When ( G > 0 ), there will be thrust · When ( G = 0 ), there is no force At the point where G = 0 is called the the equilibrium position. There are two types of equilibrium position: sustainable ( R2) and non-sustainable ( R1 , R3). · At R2: If the moving object moves away from M, it is pulled in. If it goes in the direction of movement near the M, it will be pushed away. As a result, it simple harmonic motion around the equilibrium position R2. The amplitude of this simple harmonic oscillation can be very large. · At R1 and R3, if the object deviates from the equilibrium position, it will be pulled in or ejected. The connection of objects in galaxies is similar to the bonding of atoms in the metal network. Thus, galaxies can exist in all different shapes. In the distance from M to R1 is equal to L1. G<0 and R1 are said to be boundaries of Oort cloud because matter outside of R1 would be pushed out of the solar system. So: R1 = 1.ly Is gravitational constant a constant? All experiments to find this constant are done at very small distances. This is a shortcoming in science. At great distances, humans rely on the motions of planets to find G. The law of Kepler 3 shows us that G is not a constant: Recently, Pioneer 10 and Pioneer 11(Pioneer anomaly) show that G increases with distance. Absolute values of G tend to increase with distance. G decreases to zero and changes the sign (negative, positive) when passing through the equilibrium point. (See the illustration below). The gravitational constant G is forced to increase to serve the following problem: It is the energy conservation of gravitational waves. If : L1 = L2 = L3 =... = Ln, then G is forced to rise too fast. This is unreasonable. Therefore, L must also increase along with G. I have an assumption that: Ln+1 = K . Ln with K > 1. I'm leaning toward the plan : K = 3 “This is just a guess, because most of the objects at distance 3ly have a direction of motion away from the solar system” As G increases with distance, all gravitational calculations will no longer be valid. Gravity is much bigger than what we think. This is dark matter. Gravitational field is not only gravity but also repulsive force. This is dark energy.