-
Posts
11 -
Joined
-
Last visited
Content Type
Profiles
Forums
Events
Posts posted by deesuwalka
-
-
[latex] \int\limits^2_0 \dfrac{x^2}{x^2-2x+2} dx [/latex]
[latex] =\int\limits^2_0 \dfrac{x^2-2x+2+2x-2}{x^2-2x+2} dx [/latex]
[latex] =\int\limits^2_0 1+ \dfrac{2x-2}{x^2-2x+2} dx [/latex]
[latex] =\int\limits^2_0 dx+\int\limits^2_0 \dfrac{2x-2}{x^2-2x+2} dx [/latex]
Let [latex] t=x^2-2x+2 [/latex]
[latex] dt=(2x-2)dx [/latex]
[latex] =\bigg[x\bigg]^2_0+\int\limits^2_0\dfrac{dt}{t} [/latex]
[latex] =2+\bigg[\ln\,t\bigg]^2_0\;\;\implies\bigg[\ln(x^2-2x+2)\bigg]^2_0 [/latex]
[latex] =2+\bigg[\ln\,2-\ln\,2\bigg] [/latex]
[latex] =2+0=2 [/latex]
0 -
Here is the solution-
[latex] -8=\dfrac{3}{19}n [/latex]
Now, multiply both sides by [latex] 19 [/latex]
[latex] -8\times 19=\not19 \times\dfrac{3}{\not19}n [/latex]
[latex] -152=3n [/latex]
Now, divide both sides by [latex] 3 [/latex]
[latex] \dfrac{-152}{3}=\dfrac{3n}{3} [/latex]
[latex] \dfrac{-152}{3}=n [/latex]
0 -
You have to switch the [latex]x[/latex] and [latex]y[/latex], and then solve for [latex]y[/latex].
[latex]y=x^7+x^5 [/latex]
[latex]x=y^7+y^5 [/latex]
[latex]x=y^5(y^2+1) [/latex]
I think it can't be solved farther.
0 -
Right, there are millions of books available. I think you should prefer online study, there are many sites which help you
0 -
[latex] \frac{x+y}{x-y}\times\frac{x-y}{x+y} [/latex]
[latex] =\frac{\not x+\not y}{\not x-\not y}\times\frac{\not x-\not y}{\not x+\not y} [/latex]
[latex]= 1 \times 1[/latex]
[latex]= 1 [/latex]
0 -
How many equations would you say this expression represents, 1 2 or 3 or more?
[math] \frac{x- x_{1} }{ x_{2}- x_{1} } =\frac{y- y_{1} }{ y_{2}- y_{1} }=\frac{z- z_{1} }{ z_{2}- z_{1} }[/math]
We can read the equations three types,
[latex] \frac{x- x_{1} }{ x_{2}- x_{1} } =\frac{y- y_{1} }{ y_{2}- y_{1} } [/latex]
[latex] \frac{x- x_{1} }{ x_{2}- x_{1} } =\frac{z- z_{1} }{ z_{2}- z_{1} } [/latex]
[latex] \frac{y- y_{1} }{ y_{2}- y_{1} }=\frac{z- z_{1} }{ z_{2}- z_{1} } [/latex]
So, I think it would be 3 equations.
0 -
Use order of operation, i.e.,PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction)
[latex] 36\div 6(2+2+2)= ? [/latex]
First, Parenthesis-
[latex] =36\div6(6) [/latex]
Now, between multiplication and division, we apply operation which comes first, here division comes first so we apply division-
[latex]= 6(6) [/latex]
Now, applying multiplication-
[latex]= 6(6)\;\;\implies 6\times6=36 [/latex]
I hope it' ll help.
0 -
We substitute [latex] \sqrt{9-x^2} [/latex] by [latex] x= 3sin\theta [/latex] because a trigonometric substitution</a> helps us to get a perfect square under the radical sign. This simplifies the integrand function.http://www.actucation.com/calculus-2/indefinite-integration/basic-methods-of-integration/integration-by-substitution-of-trigonometric-functions
Now, we can simplified it easily,
[latex] \int\sqrt{9-x^2}\;\;\implies\int\sqrt{3^2-x^2} [/latex]
[latex] \int\sqrt{3^2-x^2}\;\implies\sqrt{3^2-(3sin\theta)^2} [/latex]
[latex] =\sqrt{9-9sin^2\theta} [/latex]
[latex] \sqrt{9-9sin^2\theta}\;\;\implies\sqrt{9(1-sin^2\theta)}\;\;\implies\sqrt{9cos^2\theta}\;=\;\int 3cos\theta [/latex]
I hope it' ll help.
1 -
You can simplify it easily,
[latex] \frac{48}{2y} [/latex]
Write this as,
[latex] \frac{48}{2}\times\frac{1}{y} [/latex]
Now, simply divide 48 by 2 and then multiply,
[latex] 24\times\frac{1}{y}=\frac{24}{y} [/latex]
I hope it' ll help.
0 -
1. It's not an even number because it ends with 1, it's an odd number
3. It's not a prime number because it's divisible by 1,111,111 other than 1
0
How can i check percentage problems online?
in Mathematics
Posted
Use percent calculator-
http://www.math.com/students/calculators/source/3percent.htm