apixy

I came up with the equation, for the test in 2 days, and to verify it I searched it up and found this. I came up using this... [math] E = pc [/math] We know 2 equations that are true, and they are: [math] E=\frac{hc}{\lambda} [/math] [math]... \lambda=\frac{h}{p} [/math] Substitute and you get your equation really... [math] E=\frac{hc}{\frac{h}{p}} [/math] Which is equivalent to [math] E=\frac{hpc}{h} [/math] The 2 'h' cancel out to leave you with [math] E=pc [/math]