tieywhiey

1. The problem statement, all variables and given/known data

An ice cube melts in a 10oC glass of water (mass of water is 225g). If
the ice is allowed to melt completely, what will the final temperature
of the water be? (we're told that the mass of ice can be ignored)

Ti = 10oC
Latent heat of fusion = Lf = 334000 J/kg
specific heat capacity of water = C = 4180 J/kg/oC
mass of water = Mw = 0.225kg


2. Relevant equations:

QH = sensible heat = mC(T2-T1)
QE = latent heat = m*Lf


3. The attempt at a solution

I have figured out an equation that requires the mass of ice to be
included, however we've not been given the mass of ice (and are told
to ignore it), so I'm not sure how to create an equation that ignores
the mass of the ice.

Since we can assume this to be a closed system, the heat lost by the
water will equal the latent heat going into melting the ice and
heating this resultant water to the final temperature


Q1 = energy req'd to melt ice = Lf*Mice
Q2 = energy req'd to warm resultant water to final temperature = Mice
*C *( 0 - Tf )

Q3 = energy lost by water in the glass = Mwater * C * (Ti - Tf)

Q1 + Q2 = Q3

(Lf*Mice) + (Mice * C * (Tf - 0) = Mwater * C * (Tf - 10)


How can the Mice be ignored here?? the energy is dependent on Mice! Am I missing something?