tieywhiey

1. The problem statement, all variables and given/known data An ice cube melts in a 10oC glass of water (mass of water is 225g). If the ice is allowed to melt completely, what will the final temperature of the water be? (we're told that the mass of ice can be ignored) Ti = 10oC Latent heat of fusion = Lf = 334000 J/kg specific heat capacity of water = C = 4180 J/kg/oC mass of water = Mw = 0.225kg 2. Relevant equations: QH = sensible heat = mC(T2-T1) QE = latent heat = m*Lf 3. The attempt at a solution I have figured out an equation that requires the mass of ice to be included, however we've not been given the mass of ice (and are told to ignore it), so I'm not sure how to create an equation that ignores the mass of the ice. Since we can assume this to be a closed system, the heat lost by the water will equal the latent heat going into melting the ice and heating this resultant water to the final temperature Q1 = energy req'd to melt ice = Lf*Mice Q2 = energy req'd to warm resultant water to final temperature = Mice *C *( 0 - Tf ) Q3 = energy lost by water in the glass = Mwater * C * (Ti - Tf) Q1 + Q2 = Q3 (Lf*Mice) + (Mice * C * (Tf - 0) = Mwater * C * (Tf - 10) How can the Mice be ignored here?? the energy is dependent on Mice! Am I missing something?