dirbax
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Hi friends
I am trying to construct a new number set which dosn't have the problem
of division by zero and the square root of negative value
so here is the basic
All arithmitic rules and notions are the same as those of Reals set
except the following statements
0^2=1
if a and b are positive reals and a*b=c
then
a * -b = c "if a>b"
a * -b = -c "if a<=b"
-a * -b = -c
if a=b^n then Root(a) =b "without absolute value"
The rest is the same as the traditional R set
so as a result we have this solultions for old problems :
SquareRoot(-1)=-1 " since -1 * -1 = -1 "
1/0 = 0
0^0 = 0^(1-1) = 0^1 * 0^-1 = 0 * 0=0
So is there any chance this can be correct or at least can be changed so it respects the norm ?
thanks
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in Mathematics
For one abs() isn't smooth, at all, neither is ceiling().True , I am still working on it in order to minimise the number of functions such as ceil and abs which use semantic definition .
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Yes but I still should mention them since I am making the basis of DIMD, an other point is trying to avoid semantic presentation of functions such as
this and go for smooth calculations
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in Mathematics
I am trying to create a new math branch DIMD
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Hi , I am working on some math stuff and I need to check some points ,
so are theses formulas correct ?
ISZ(x) : is it 0 ?
isz (x) = cos ( pi * ( (2*ceil( abs(x) ) + 1)) / 2 ) / cos(1)
Ins : Real number x
Out : 1 if x=0 , 0 if x <> 0
---------------------------------------------------------------
SGN(x) : Sign
sgn(x) = abs(x) / ( x + isz(x) )
Ins : Real number x
Out : 1 if x>0 , 0 if x = 0 , -1 if x < 0
more here
thanks
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New number set
in Applied Mathematics
Posted · Edited by dirbax
Thanks DH , what about the new rules of multiplication isn't it a good way to drop out complex numbers ?
and what if we add the rule 0^-1=1 ?