david345

Nice try Michael, In the rest frame [math]\tau=t[/math] [math]x^0=ct[/math] for the rest frame [math]U^0= dx^0/d\tau =cdt/d\tau=c\gamma[/math] Cancelling out the c's [math]dt/d\tau=\gamma[/math] Because we are in the rest frame [math]\gamma=1[/math] and [math]\tau=t[/math] You are saying the speed of time is one second per second. a sec per sec is not a rate. Typically [math]dt/d\tau[/math] is considered the rate of time dilation.