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HOMBA

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  1. I know that people add hydrogen peroxide to their laundry in order to clean their clothes better. How will the effectiveness of H2O2 change according to ice cold water, room temp water, and boiling water? Wouldn't it "denature" when the temperature is too high? Or would increasing the temperature be beneficial no matter what?
  2. Hi I am having some trouble with one particular question. The question is: What is the oxidation number for the atom N is KNO2? This is the explanation I got. It looks like we have 2 unknown oxidation numbers (K & N), but the truth is that there is only one unknown (N). This is because KNO2 is a polyatomic (because it is called potassium nitrite, & nitrite is a polyatomic ion). Since polyatomic molecules are ionic, this means we know that the oxidation number of K must be +1 by the uncriss-crossing rule. We then look at O & its oxidation number is -2. The molecule is neutral, so the algebraic expression equals 0. We then solve as usual. I understand every line of that explanation except how we find the oxidation number of K. How do we use the uncriss-crossing rule to find that K has a charge of +1? Thank you in advance!
  3. For my biology lab, we had to find the pH and its effect on amylase activity. I used 1mL of acidic/basic/neutral starch solution and 3mL of 5% amylase solution. After combining the two solutions, I waited 50 minutes for the reaction to occur. (We cannot change the temperature. Therefore, room temperature) After 50 minutes, I used the Benedict's reagent and heated it to see the colour change in the solution. However, I did not observe any colour change. My hypothesis was that the neutral solution will have more monosaccharides for its product! However, when I did Lugol's test (iodine), all three solutions tested that there is no starch in the solution. Does that mean that the product is a disaccharide? I am confused with the results. How should I modify my lab in order to see changes through the Benedict's reagent, not Lugol's reagent? Thank you in advance!
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