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shott92

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Everything posted by shott92

  1. hi the cheers sorry when i typed ( r ) without the spaces it automatically made it to a ® :/ the Fc is the lateral force from the center of the corner outwards (the centripetal force) as such i am basing this not on centrpetal acceleration just the given force in Newtons, the velocity is perpendicular to the plane of the diagram but technically irrelevant as this should be able to be solved in 2D, the velocity and radius of the corner though give the lateral force, friction is the centrifugal force or the force that allows the bike not to slip hence the friction must be higher than Fc or slip would occur, and for the given point in time the bike is in equilibrium as the lean angle is definite as are all the other factors the bike is only in forward motion for this practice the forward velocity as far as i can tell is irrelevant this scenario could be mimicked by the bike being stationary but leant over to a certain angle then a force pushing onto the seat (down through the CoG to the contact patch) the wheel would still want to twist to an upright position at both A (the contact patch) and B the spindle or hub on the forks, as i said this is what im trying to figure i'm sure there should be a simple moment around a point equation to calculate this but i cant figure what value it is i actually need :/ sorry for being awkward but i've spent the last 6 months calculating many force equations for most of the degrees of freedom on the bike across the x,y and z axis im now trying to calculate the rotational forces and having abit of difficulty here im coming to the end of my 2nd year at university and this is a project i set myself as such there is no help sheets that i can refer to and the magnitude of books i have dont have the equations i need for this task, please accept my appolagies for any unclarity but this unclarity is why i am asking for help, and your time is much appreciated so thank you
  2. hi well that is a little more advanced than i was hoping, the frictional / tractive for would be the force that is opposing Fc i assumed that tractive force would have to be higher but V = Sqrt((mu)gr) for this instance i am using (mu) the traction co efficient as 1.3 Fc = (sprung mass *v^2)/®*(wheelbase-CoG(X))/wheelbase)cos(r/(sqrt(CoG^2+r^2)) tractive force = 1/2 Cog(x)(sqrt(g^2)+(V^2/r)) Fsr = mg(wheelbase-CoG(X))/wheelbase)+Frontal area*coeffiecient of drag*(Cog(y)/wheelbase) the reason i didnt put these equations in is becuase of the readability and i am not sure i can assume it would have been newtons solution as thats all we have been taught and i was planning or attempting to work the moments out as simply as possible would there be an easier way if we was to assume a constant state? this is what i was trying to do as i would be able to find for Vmax and a specific lean angle hoping that it would give a useable single point answer rather than finding for a certain displacement or deriving for a point along the corner i hope this provides enough information for you to be able to help me (also if i have mucked up one of the above equations then let me know but i have reworked the a few times they seem accurate) thanks very much the help is hugely appriciated
  3. hi guys this is an image of the rear wheel of a push bike going into a corner as well as what i think are relevant forces, i need to calculate the moments or torque at A (the contact patch) and B (the hub centre) this is to calculate the force on the left hand side of the frame and right hand side of the frame while in a corner Fsr = the force going through the suspension Fc = lateral cornering forcer on the rear wheel phi = lean angle MG = mass & gravity t = the cross sectional radius of the tyre i can and have calculated the above parameters through lot of prior equations that take into account the wheelbase, velocity, friction, radius of the turn ect. but i think that the above are the require ones to calculate this... if there is an easier way please let me know im sure its quite simple really but i have either over thought it are just been daft cheers for any help guys but could you please explain your reasoning behind your answer so that i can verify it please https://s.yimg.com/hd/answers/i/7c911b9cff554eabad1ca29c0f9e8161_A.jpeg?a=answers&mr=0&x=1398491203&s=49df46fb82b50fa73242ec5bd28516c4
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