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pzkpfw

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Posts posted by pzkpfw

  1. 19 minutes ago, MigL said:

    Really ?
    I'm going to need a citation for that.
    Not that I don't believe you; I just always thought he was really native American of the Lakota tribe.

    https://edition.cnn.com/2023/02/28/us/crying-indian-ad-campaign-cec/index.html#:~:text=Born Espera Oscar de Corti,campaigns is pictured in 1986.

    I learned about this from an episode of "American Pickers" where they happened on an old tent of his.

     

     

    On the OP: birth rates in the "more developed" countries falls. Look at the population crisis in many places like Japan. It gets expensive to raise kids, you don't need them to (directly) look after you when you are old, and people simply have other things to do. Equal rights and opportunities for women helps. i.e. given the choice to have kids. The idea in the OP that women need to be lectured on birth control is a very colonial view.

    So the real trick, will be to develop all nations (so birth rates look after themselves) - but somehow without everyone consuming all resources and polluting like it's 19xx all over again.

  2. Once you stick a battery in, then regenerative braking starts having value, so no more of your energy goes to making brake pads get hot.

    Maybe then it's seen more as a battery driven bike, where your pedaling is a range extender?

    I like the idea that (at the cost of more weight) this would make it possible to stick another motor in the front wheel - a 2 wheel drive bike? Maybe good in mud?

    I don't have the skills to calculate which is best.

     

  3. 34 minutes ago, Aetherwizard said:

    ...

    Chronovibration is a constant. Since it does not change, there is nothing to conserve. In Relativity theories, chronovibration is the physical cause of the constant photon speed in local space. Chronovibration is the reason the Relativity theories work.

    According to relativity, if you and I are in relative motion, we both consider our clocks normal (ticking one second per second) and we both consider each others clocks to be slow.

    How does the above work with that?

  4. I read the OP as two parts: (paraphrased) A=heard that cosmic rays includes neutrons, B=stuff about neutrons that makes that hard to believe.

    While B included correct information about neutrons, it seemed possible the whole question might be a red herring if A was just that simple mix up.

    But I will back away slowly now.

  5. Radio works at the speed of light.

    Lasers are also already used for some communication.

    No time travel involved.

    Edit: my comment above was posted before the message above was seen.

    What do you mean by "binary light frequency"?

    And, it's still not clear why you think/thought information would be received before it is sent.

  6. 42 minutes ago, joigus said:

    It was, because otherwise one rocket's relative speed to the other one is equal and opposite to the converse, no matter what relativity principle you use (Galilean or Einsteinian).

    It's exactly as Swansont said with 0.5, 0.5, giving 0.8 (in units of c)

    It's perhaps an illuminating exercise to do it with 

    0.99999 and 0.99999. It gives (0.99999+0.99999)/(1+0.99999*0.99999) = 0.9999999999

    (in units of c) which is practically just c.

    But, and here's what interesting, with small velocities as compared to c.

    0.00001, 0.00001, it gives (0.00001+0.00001)/(1+0.00001*0.00001)=0.00002000000000

    which is so close to the simple addition of velocities that nobody could tell the difference. That's why our intuition tells us velocities are additive.

    Just to link it up for Moontanman, the bits I bolded above are worked examples (reverse order) of what I described in the 3rd post:

    Quote

     

    ... Where v and u' are small fractions of c, this ends up being a division by almost 1, i.e. at regular day to day speeds, it hardly makes a difference.

    But where v and u' are large fractions of c, that becomes close to a division by two, i.e. you can add two speeds close to c, and still get a speed close to c. ...

     

     

  7. For Moontanman: in the above, that 0.5c is as measured by the space station, and each rocket to the station; and the 0.8c is as measured by each rocket to the other rocket.

    For the space station, the closing speed of the rockets (which is not the speed of either rocket) is c.

  8.   

    15 minutes ago, Moontanman said:

    The observer is on each rocket, the rocket judges its own speed by its departure point, from my point of view it looks like the combined speeds would be greater than c, I understand this is not possible except in my frame of reference but what would the two space craft measure each others speed as? 

     

    I think you really need to get clear on the difference between measuring closing speed (which is the speed of a gap, a nothing), and the speed of a thing.

    And it depends a lot on who is observing.

    Say the fastest car in the World can do 500 km/h. Stick two of them on a track facing each other and run them, at top speed.

    The gap between (from the point of view of the track) them is decreasing at 1000 km/h. Hang on! That's faster than the car can go! But that 1000 km/h isn't the speed of either car according to the track. Sure, if the track considers it from the point of view of one of the cars, then the other is getting closer at 1000 km/h, but that reference point is moving according to the track. It's an illusion, if you like.

    Relativistic addition comes in (in this scenario) when you consider the point of view from one of the cars. Each car can consider itself as still, and the other car moving towards it. But note that the track is also moving towards it! The track is moving towards each car at 500 k/h, and the other car is moving towards it at 500 km/h relative to the track.

    And that's where you cannot (at relativistic speeds where it starts to matter) just add the 500 and 500. Each car will consider the other car approaching at 999.99999 km/h.

    The track considers the closing speed as 1000 km/h, and the cars consider the other is approaching at 999.99999 km/h. These are different numbers.

  9. You are confusing yourself by being imprecise. You cannot make your mind up on whose point of view is involved. Who is the observer, one of the rockets? Or someone else?

     

    (And: As noted before, someone else (not in the rockets) can consider the rockets as approaching each other at more than c, closing speed can be as much as 2c.)

     

  10. Just now, Moontanman said:

    Ok, so they couldn't measure their relative speeds without the station to compare it to?

    No they can measure speed relative to themselves, as in your first post.

    In your first post, rocket A (to give it a name) measures rocket B to be coming at 0.99999c.

    And vice versa.

     

  11. 4 minutes ago, Moontanman said:

    Would the space station influence the speed the two space craft measure on each other? 

    The existence of the space station doesn't affect anything. But if that's what speeds are being measured against, it changes your scenario.

    You started off saying each rocket measures the other as going some speed. Well then that's just what they measure.

    But if you change the scenario so that each rocket measures some speed from themselves to the station, and the other rocket as at some speed relative to the station, then yes, each rocket needs to use the proper formula to determine the speed of the other rocket relative to themselves.

  12. Edit 2: darn, misread. I'll leave this here but as swansont points out I've misread your question.

    [

    The formula is here:

    https://en.wikipedia.org/wiki/Velocity-addition_formula

    The "interesting" bit (to me) is the division by  1 + ( ( v x u' ) / ( c x c ) )

    Where v and u' are small fractions of c, this ends up being a division by almost 1, i.e. at regular day to day speeds, it hardly makes a difference.

    But where v and u' are large fractions of c, that becomes close to a division by two, i.e. you can add to speeds close to c, and still get a speed close to c.

    As exchemist points out, you need to be careful who thinks what speed is what.

    edit: but don't mix this up with closing speed, that can be as much as 2c.

    e.g. someone considering themselves as still, who sees two rockets coming towards them from opposite directions, each at 99% of c, does see the gap between the rockets decreasing at close to 2c. But that's not the same as seeing a thing moving faster than c; neither that middle observer nor either rocket sees any rocket going over c here.

    ]

  13. 6 hours ago, DanMP said:

    ... The acceleration in order to return is considered important for the outcome. ...

    Are you claiming the acceleration is a direct cause of the differential aging in the twins' paradox?

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