nindiya

my teacher said that the delta T value for cal = delta T acid (which was 6.1) I also calculated Ccal in a previous question and it was 30.269 which was the value I substituted in this equation above. I've attached my calc. *Note: the value of 0.063moles is the moles remaining of HCOOH

My teacher gave us an equation: nhcoohdeltaHhcooh+oh + nh30deltaHh30+oh = -(CcaldeltaTcal + cwaterVaciddeltaTacid + cwaterVbasedeltaTbase) & told us to find enthalpy of neutralization fo formic acid. given: hcooh + oh----h2o + hcoo h30+oh----2 h2o hcooh: t1=21.4, t2= 27.5, delta T=6.1 (* this was also the delta Tcal) naoh: 20.4, t2= 27.5 , delta T= 7.1 This is the information I calculated: 1. initial moles - nh30= 0.0632 (0.075mol - 0.011748mol) (which my teacher said to use the equation above with. We had to interpolate deltaHhcooh+oh ( which = -58517) However, I plugged in the values and got -57474.58. Please help. (* how to do the proper procedure)