md2

i supose howard web dont fair ride the match

diameter of sphere is 2 pi r, but from what point of view

next values : I : 2 + 2 ^ 2 II : 2 + 2 ^ 3 III : 2 ^ 1 + 2 ^ 2 + 2 ^ 3

a ^ 2 = d ^ 2 / 2

high of triangle same-side around the circle is 3 r, to 2r ( 2 ray of circle ) 2 ray of circle to diagonal of square inside the circle is 2 to 2 / sqrt(2)

( 2 ^ 2 ) ^ 2 is not like 2 ^ 3 in dimenosion for examp

collision of hadrons, but what is it hadron ?

suggestion : 2r is diagonal of square inside the oval

based on ricle r = 1, course is side of square around of circle, and diagonal from eaual of area of circle, this three values are course of next circle rays and 2 r / sqrt ( 2 ) = sqrt ( 2 ) for r = 1

is it a dependence between d ( diagonal of square from equal of area of circle ) to r ( ray of this circle ) d / r pi * r ^ 2, pi * sqrt(2) ^ 2, d = sqrt(2) * d ( for third value ) ....

b = ( x - 3 ) ^ 2 + b