frankenstein18 Posted November 24, 2015 Share Posted November 24, 2015 Can someone tell me if I'm on the right track with these intramolecular reactions? For a) I think that an epoxide is formed after NaH takes a Hydrogen from the OH substituent and then the electrons travel making the Cl leave. Then for b I know an epoxide can't form since the OH and the Cl are on the same side. I think the NaH would take the H, so would the product be a resonance structure??? For c. I think it's a 5 carbon hetero-cyclic ring with an Oxygen closing the ring + NaH2 and Br- And for d. I think another hetero cyclic ring happens but I don't know what it would look like.I don't know it's substituents or how long it would be since it's not a long chain like how c was. Am I in the right direction? Link to comment Share on other sites More sharing options...
BabcockHall Posted November 24, 2015 Share Posted November 24, 2015 I think that when sodium hydride accepts a proton, the side products will be Na+,Br- and H2 gas. I see no reason why an epoxide could not form in d. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now