If the Hubble constant were to be 2.0 x10^-18 s^-1, what would the age of the universe be, in seconds x10¹⁷? (1. ) (Find the number by taking the inverse of the Hubble constant. That means divide 1 by the Hubble constant. Just write the whole number that you get as a result in the following blank, with no decimal points or zeros.)

What would that age of the universe be in billions of years? (2. ) (Find the number by dividing your previous answer by the number of seconds in a year. Round the resulting billions of years off to the tenths; for example if you calculated 19,779,300,000 years, which is 19.7793 billion years, you would just write 19.8).

If the Hubble constant were to be 2.5 x10^-18 s^-1, what would the age of the universe be, in seconds x10¹⁷? (3. ) (Just give the whole number, no decimal points or zeros.)

What would that age of the universe be in billions of years? (4. ) (Round the billions of years off to the tenths.)

The current actually known value of the Hubble constant, to the tenths, is 2.3 x10^-18 s^-1.

From that value, what is the age of the universe be, in seconds x10¹⁷? (5. ) (Write out the number including the five digits after the decimal point.)

And finally, given that actually known value of H₀, what is the age of the universe, in billions of years? (6. ) (Round the billions of years off to the tenths.)

Edited August 8, 20169 yr by chey

You have to make a go at answering - we won't do the work for you.