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Redox solutions lab Keq

banana!
in Homework Help

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Hello,
I am trying to figure out how to calculate keq for a redoxs soultions lab we did in my uni with copper (i) chloride mixed with 60 mL of distilled water. We were asked which redox reaction happened? (precipitation? ) and to calculate keq
Im not really sure how to do this.

so first I wrote what happened and then I thought I had to calculate the moles of the species?

so 0.01 moles of CuCl (i think) and 0.003 moles of water?

 

2CuCl + H2O = Cu2++ 2Cl + H2O

then im not sure of my next step?

UPDATE:
So then I can put it into this form no?

Keq = [Cu2+][2Cl-]/ [CuCl]

i dont understand why it is Cu2+ and 2Cl. isnt there a value for the separation of CuCl in the first place?

Edited by banana!

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