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Reaction with Dimedon

C2H5OH
in Organic Chemistry

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Hello everybody :)

 

I have a problem with one exercise.

Dimedon shall react with NaOH and an excess of Br2. What is the product of the reaction?

 

I thought about deprotonating the Dimedon between the two Keto-groups and form the enolat. But does the Br2 is added then or does something else happens first?

 

Thanks for your help :)

 

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