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Molybdate-phosphate reaction

shafaifer
in Inorganic Chemistry

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Is something here correct?

Let us say you have this salt: Na3PO4, to this salt you add HCl(aq):

Na3PO4(s) + 3HCl(aq) --> 3NaCl(aq) + PO43-(aq) + 3H+(aq) (equation 1)

 

Now phosphate reacts with added molybdate, then added HCl(aq):

 

PO43-(aq) + 3NH4+(aq) + 12Mo2+(aq) --> (NH4)3[PMo12O40](s) (equation 2)

 

 

According to a lab manual, the product on the right side of the reaction in Eq. 2 is correct. The manual only says that phosphate reacts with molybdate and creates the product in equation 2 - not what the reactions in question look like. I cannot balance the left side of Eq. 2, how is it done?

 

Best regards,

 

Shafaifer

Edited by shafaifer

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