umer007 Posted February 25, 2005 Share Posted February 25, 2005 The arithmetic sequence a, a+d, a+2d, a+3d,...., a+(n-1)d has the following properties: When the first, third, and fifth and so on terms are added, up to and including the last term, the sum is 320. When the first, fourth, seventh and so on terms are added, up to and including the last term, the sum is 224? What is the sum of the whole sequence? Im clueless, can ne1help. Thx alot. Link to comment Share on other sites More sharing options...
fuhrerkeebs Posted February 25, 2005 Share Posted February 25, 2005 It depends on how many terms are in the sequence. Assuming that the last term is a+(n-1)d, you get the values: a=512/(n+1) d=-192/(n2+n) Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now