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Gauge Theory and fundamental fields not being able to be measured


Stratus

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Hello again everybody, i'm back again for another question that i've come across in my studies.

 

According to many books I've read, a feature of gauge theory is that the fundamental field from which the excitations come from can not be measured in any way, but change by a gauge transformation. Whereas the excitation's observable quantities like charge and velocity can be measured, but can not be changed by a gauge transformation.

 

That makes sense to me, but this next part is where I have trouble.

 

I came across this problem in a book, then went to Wikipedia looking for an answer to my question. In Wikipedia's words

"For example, in electromagnetism the electric and magnetic fields, E and B, are observable, while the potentials V ("voltage") and A (the vector potential) are not.[3] Under a gauge transformation in which a constant is added to V, no observable change occurs in E or B."

Is this saying that it's impossible to measure the potential V, and in that case, how do voltage meters work? I'm not familiar with vector potential yet myself, but I imagine that there would be a way to calculate or measure it as well.

 

As well, I understand a gauge transformation is a "change in a fields configuration". what is referred to here as being configured differently? I don't understand what is being configured differently in one of the fundamental fields?

Thank you

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A is the electromagnetic potential, it is a field on space-time. It is not the potential difference.

 

I don't know how much you know about differential forms, but let us consider the de Rham differential d which takes an n-form to an n+1 form. The key property is that dd =0, in fact that is all that we really need here.

 

The electromagnetic field A is a one-form and the field strength is F(A)=dA. Now consider A'= A+df, where f is a zero form. You see that F(A') = d(A+df) = dA =F(A). This is a gauge transformation and you see that the field strength is unchanged.

 

Now the components of F are related to the electric and magnetic fields.

Edited by ajb
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A is the electromagnetic potential, it is a field on space-time. It is not the potential difference.

 

I don't know how much you know about differential forms, but let us consider the de Rham differential d which taken an n-form to an n+1 form. The key property is that dd =0, in fact that is all that we really need here.

 

The electromagnetic field A is a one-form and the field strength is F(A)=dA. Now consider A'= A+df, where f is a zero form. You see that F(A') = d(A+df) = dA =F(A). This is a gauge transformation and you see that the field strength is unchanged.

 

Now the components of F are related to the electric and magnetic fields.

hmm i don't think i'm quite there yet, as I somewhat understand the equations, but am not in calculus now. Hopefully I'll be able to re-read this later and it would make more sense (i'm in trig/pre-calc right now). I know a little bit about differential forms, but not quite enough right now.

 

seems like most things in physics are currently over my head, but hopefully it will make more sense as i proceed in my math studies. I always have a habit of trying to skip the basics and understand the complex stuff, one of my character flaws.

 

right now I think i'll just continue trying to understand what I can until I get far enough into math

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right now I think i'll just continue trying to understand what I can until I get far enough into math

Differential forms are considered quite advanced mathematics for standard physics, though they are very important.

 

The key here is we have a map d and this map "squares to zero" thus d(A +df) =dA. For EM theory this is what we mean by a gauge transformation. You see you have the freedom of adding a df to every potential A and you do not change the field strength F. This means that physically you cannot define A absolutely, you always have the ambiguity up to the function f.

 

Picking a gauge is really just declaring an A and fixing it. That is you remove the freedom of adding a df. None of the physics should depend on this choice.

Edited by ajb
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Differential forms are considered quite advanced mathematics for standard physics, though they are very important.

 

The key here is we have a map d and this map "squares to zero" thus d(A +df) =dA. For EM theory this is what we mean by a gauge transformation. You see you have the freedom of adding a df to every potential A and you do not change the field strength F. This means that physically you cannot define A absolutely, you always have the ambiguity up to the function f.

 

Picking a gauge is really just declaring an A and fixing it. That is you remove the freedom of adding a df. None of the physics should depend on this choice.

Ah, so if I understand what you're saying, that because we can always add another df to A, we can not say that we know exactly what A is. But, because adding another df effectively makes no different, it does not change the field strength F? So, a transformation would really just be having the freedom to add another df to the equation? At least in EM theory?

 

Also, if I can ask, which areas of mathematics are these ideas normally covered? Such as, which areas of mathematics are most commonly used in physics? Ideally particle physics.

Edited by Stratus
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Ah, so if I understand what you're saying, that because we can always add another df to A, we can not say that we know exactly what A is. But, because adding another df effectively makes no different, it does not change the field strength F? So, a transformation would really just be having the freedom to add another df to the equation? At least in EM theory?

Yes, that is the idea.

 

It is a little more complicated for general gauge theories, but the idea is the same.

 

Also, if I can ask, which areas of mathematics are these ideas normally covered? Such as, which areas of mathematics are most commonly used in physics? Ideally particle physics.

Differential geometry.

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